<?xml version="1.0" encoding="UTF-8"?>
<archimedes xmlns:xlink="http://www.w3.org/1999/xlink">
<info>
<author>Stelliola, Niccolà Antonio</author>
<title>De gli elementi mechanici</title>
<date>1597</date>
<place>Naples</place>
<translator/>
<lang>it</lang>
<cvs_file>stell_mecha_041_it_1597.xml</cvs_file>
<cvs_version/>
<locator>041.xml</locator>
</info>
<text>
<front>
<section>
<pb xlink:href="041/01/001.jpg" id="p.0001"/>
<p id="N1001B" type="head">
<s id="N1001D">DE GLI <lb/>ELEMENTI <lb/>MECHANICI<lb/><figure id="id.041.01.001.1.jpg" xlink:href="041/01/001/1.jpg"/><lb/></s>
<s>La ſtatera. </s>
<s>Leua. <lb/></s>
<s id="N1002B">Raggi nell'aſſe. </s>
<s id="N1002D"> Rote vettiue <lb/></s>
<s id="N10030">Taglia. </s>
<s id="N10032">Rote motiue. <lb/></s>
<s id="N10035">Cugno. </s>
<s id="N10037"> Vite. </s></p><p id="N10039" type="head">
<s id="N1003B"><emph type="italics"/>DI C. ANTONIO STELLIOLA. <emph.end type="italics"/></s></p><figure id="id.041.01.001.2.jpg" xlink:href="041/01/001/2.jpg"/>
<p id="N10044" type="head">
<s id="N10046">IN NAPOLI, Nella Stamparia à Porta Regale <lb/>M. D. XCVII. </s></p>
</section>
<pb xlink:href="041/01/002.jpg" pagenum="1"/>
<section>
<p id="N1004E" type="head">
<s id="N10050"><emph type="italics"/>PROPOSITIONE <lb/>di tutta l'opera. <emph.end type="italics"/></s></p><p id="N10058" type="main">
<s id="N1005A">Cerchiamo come poſſa la potenza <lb/>minore vincer di forza la maggiore: <lb/>e la potenza piu tarda, vincer di mo­<lb/>uimento la piu veloce. </s>
<s id="N10062">e queſto con <lb/>Leue, Taglie, Viti, Rote, e tutti inſtrumenti che <lb/>moltiplicar poſſono il momento, o della forza, <lb/>o della velocità. </s>
<s id="N1006A">Qual ſoggetto communemente <lb/>gli antichi chiamarono Mechaniche. </s>
<s id="N1006E">Il che tut­<lb/>to ſi tratterà ſecondo le ſuppoſitioni fatte de mo­<lb/>menti, o per linee parallelle, o per linee con­<lb/>correnti ad vn ponto, o per circonferenze d'in­<lb/>torno vn centro iſteſſo: e ſecondo il ſolito vſo de <lb/>mathematici deducendo le dimoſtrationi, e cau­<lb/>ſe de gli effetti, dalli primi e proprij principij. </s></p><figure id="id.041.01.002.1.jpg" xlink:href="041/01/002/1.jpg"/>
</section>
<pb xlink:href="041/01/003.jpg" pagenum="2"/>
<section>
<p id="N10083" type="head">
<s id="N10085"><emph type="italics"/>DEFINITIONI. <emph.end type="italics"/><lb/>I. </s></p><p id="N1008D" type="main">
<s id="N1008F">Centro di peſo diciamo il ponto, per cui il corpo co­<lb/>munque ſoſpeſo, non muta poſitione. </s></p><p id="N10093" type="head">
<s id="N10095">II. </s></p><p id="N10097" type="main">
<s id="N10099">Corpo egualmente diſteſo diciamo, che comunque <lb/>tagliato con pianezze parallele, fa figure ſuperficiali <lb/>eguali e ſimili. </s></p><p id="N1009F" type="head">
<s id="N100A1">III. </s></p><p id="N100A3" type="main">
<s id="N100A5">Applicarſi diciamo vn corpo ad vna linea, quando <lb/>detto corpo vgualmente diſteſo occupi la lunghezza di <lb/>detta linea. </s></p><p id="N100AB" type="head">
<s id="N100AD">IIII. </s></p><p id="N100AF" type="main">
<s id="N100B1">Linea di momento diciamo, per cui il centro di pe­<lb/>ſo della grauezza da impedimento libera ſi moue. </s></p><p id="N100B5" type="head">
<s id="N100B7">V. </s></p><p id="N100B9" type="main">
<s id="N100BB">Libra ò ſtatera diciamo la linea a cui ſi applicano, ò <lb/>appendono le grauezze: e che ſia ſuſpeſa da vn ſol <lb/>ponto. </s></p><p id="N100C1" type="head">
<s id="N100C3">VI. </s></p><p id="N100C5" type="main">
<s id="N100C7">E leua diciamo la linea ſoſtenuta da due ponti, o ſo­<lb/>ſtenuta da vn ponto e moſſa da vna poſſanza. </s></p><p id="N100CB" type="head">
<s id="N100CD">VII. </s></p><p id="N100CF" type="main">
<s id="N100D1">Ponto di momento diciamo nella ſtatera e leua, il <lb/>ponto, nel quale s'incontra la linea del momento, con <lb/>la linea della ſtatera. </s></p><p id="N100D7" type="head">
<s id="N100D9">VIII. </s></p><p id="N100DB" type="main">
<s id="N100DD">E ponto di appenſione: il ponto, onde perde la gra­<pb xlink:href="041/01/004.jpg" pagenum="3"/>uezza ſtaccata dalla ſtatera, o leua, nelquale iſteſſo pon­<lb/>to s'intende hauer il ſuo momento. </s></p><p id="N100E5" type="head">
<s id="N100E7">IX. </s></p><p id="N100E9" type="main">
<s id="N100EB">Et Horizonte de peſi la ſuperficie in cui le linee de <lb/>momenti tutte vanno perpendicolarmente. </s></p><p id="N100EF" type="head">
<s id="N100F1"><emph type="italics"/>Appendice. <emph.end type="italics"/></s></p><p id="N100F7" type="main">
<s id="N100F9">Dalche è manifeſto, che l'Horizonte de' momenti pa­<lb/>ralleli, ſia ſuperficie piana: e delli concorrenti ſia ſuper­<lb/>cie sferica. </s></p><p id="N100FF" type="head">
<s id="N10101"><emph type="italics"/>POSITIONI. <emph.end type="italics"/><lb/>I. </s></p><p id="N10109" type="main">
<s id="N1010B">Pigliamo nelli corpi egualmente diſteſi il centro del <lb/>peſo eſſer nella ſuperficie, che diuide egualmente la <lb/>lunghezza di detto corpo. </s></p><p id="N10111" type="head">
<s id="N10113">II. </s></p><p id="N10115" type="main">
<s id="N10117">Che grauezze eguali appeſe o nell'iſteſſo ponto, o in <lb/>ponti della libra egualmente diſtanti dalla ſuſpenſione <lb/>della ſtatera, habbiano momento eguale. </s></p><p id="N1011D" type="head">
<s id="N1011F">III. </s></p><p id="N10121" type="main">
<s id="N10123">Che nelli corpi di vna iſteſſa natura ſia proportionale <lb/>il peſo alla quantità delli corpi. </s></p><p id="N10127" type="head">
<s id="N10129">IIII. </s></p><p id="N1012B" type="main">
<s id="N1012D">E, che la grauezza appeſa non ſi fermi, ſin che il <expan abbr="cẽ­tro">cen­<lb/>tro</expan> del peſo non ſia nella perpendicolare del ponto del <lb/>ſoſtenimento. </s></p>
</section>
</front>
<pb xlink:href="041/01/005.jpg" pagenum="4"/>
<body>
<chap id="N1013B">
<p id="N1013C" type="head">
<s id="N1013E"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>I. </s></p><p id="N10146" type="main">
<s id="N10148">Se ſi togliono due quantità da due altre, che ſiano <lb/>eguali, e tra di loro, &amp; alla compoſta delle due tolte: di­<lb/>co che le reſtanti alle tolte ſcambieuolmente ſono egua­<lb/>li. </s></p><figure id="id.041.01.005.1.jpg" xlink:href="041/01/005/1.jpg"/>
<p id="N10153" type="head">
<s id="N10155"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N1015B" type="main">
<s id="N1015D"><emph type="italics"/>Siano le due quantità, A &amp; B, &amp; alla compoſta di ambe ſiano egua<lb/>li, la C D, &amp; la E F; e dalla C D, togliaſi eguale ad A, che ſia, <lb/>C G, e dalla E F togliaſi eguale a B, che ſia E H. </s>
<s id="N10165">dico che la reſtan­<lb/>te H F, è vguale ad A; e la G D, eguale a B. </s>
<s id="N10169">Si moſtra perciò <lb/>che eſſendo C D, eguale ad A e B inſieme: tolti dall'vna e l'altra ſum­<lb/>ma le A, e C G eguali: le reſtanti, B, e G D di conſeguenza ſo­<lb/>no eguali. </s>
<s id="N10171">Similmente perche la E F ſi pone vguale alle A, &amp; B <lb/>gionte inſieme; tolte la E H, &amp; B vguali: le reſtanti, H F, e A ſo­<lb/>no di conſeguenza eguali. </s>
<s id="N10177">è adunque la H F eguale a C G: e la G D <lb/>eguale ad E H. </s>
<s id="N1017B">il che hauea da moſtrarſi. <emph.end type="italics"/></s></p><p id="N1017F" type="head">
<s id="N10181"><emph type="italics"/>Appendice. <emph.end type="italics"/></s></p><p id="N10187" type="main">
<s id="N10189">Dalche è manifeſto, che le iſteſſe reſtanti ſcambieuol­<lb/>mente ſono proportionali alle tolte. </s></p>
<pb xlink:href="041/01/006.jpg" pagenum="5"/>
<p id="N10190" type="main">
<s id="N10192">Percioche eſſendo le C G H F eguali. </s>
<s id="N10194">e le G D E H <lb/>anco eguali: ma le eguali ſono proportionali: ſono <expan abbr="dũque">dunque</expan><lb/>come C G ad E H, coſi H F ad G D: ilche hauea da mo­<lb/>ſtrarſi. </s></p>
</chap>
<chap id="N1019F">
<p id="N101A0" type="head">
<s id="N101A2"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>II. </s></p><p id="N101AA" type="main">
<s id="N101AC">Se alla linea della ſtatera ſi applicano continuatamen­<lb/>te due corpi: li centri delli corpi applicati, ſono diſtanti <lb/>dal centro di tutto il compoſto, di diſtanze proportio­<lb/>nali alli peſi, pigliati reciprocamente. </s></p><figure id="id.041.01.006.1.jpg" xlink:href="041/01/006/1.jpg"/>
<p id="N101B7" type="head">
<s id="N101B9"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N101BF" type="main">
<s id="N101C1"><emph type="italics"/>Sia la linea della ſtatera, A B, l'vn delli corpi applicati ſia <lb/>B C, l'altro ſia C A, e l'applicatione del corpo B C occupi la parte di li­<lb/>nea B D, e del corpo C A, la parte A D, e diuidaſi B D, in par­<lb/>ti vguali al ponto E: &amp; A D in parti eguali il ponto F: è manifesto <lb/>che del corpo applicato à B D, il ponto del momento ſia E, e del cor­<lb/>po applicato a D A, il ponto del momento ſia F, dico che diuiſa B A <lb/>tutta per metà nel ponto G, che è ponto di <expan abbr="momẽto">momento</expan><lb/> della grauezza tut­<lb/>ta compoſta di ambedue: c'habbia la diſtanza F G a G E la ragione <lb/>che'l peſo di B C al peſo di C A. </s>
<s id="N101DA">Si moſtra percioche la ragione del <lb/>peſo di B C, al peſo di C A, e l'iſteſſa che delli corpi: e delli corpi<emph.end type="italics"/><emph.end type="italics"/><pb xlink:href="041/01/007.jpg" pagenum="6"/><emph type="italics"/>vgualmente diſteſi, e l'iſteſſa che delle linee: qual è della linea B D <lb/>a D A. </s>
<s id="N101E8">e delle loro metà di E D a D F cioè di F G, a G E: <lb/>&amp; perche ſe due quantità compongono quantità, e le metà del­<lb/>le componenti, compongono la metà della tutta: ma le metà delle li­<lb/>nee componenti ſono A F, e B E, la metà della tutta, e coſi la B G <lb/>come la A G. </s>
<s id="N101F2">perciò togliendo due quantità A F B E dalle due, <lb/>A G, G E eguali tra di loro, &amp; alla compoſta di A F, B E. </s><lb/>
<s id="N101F7">le reſtanti ſcambieuolmente ſono proportionali, e perciò F G, a G E <lb/>ſarà nell'iſteſſa ragione di B E, ad A F, cioè della doppia, B D, a D <lb/>A: qual è l'iſteſſa del corpo, B C, a C A: e della grauezza di B C, a <lb/>C A. </s>
<s id="N101FF">la diſtanza dunque F G, alla diſtanza E G, ha la ragione che'l <lb/>peſo di B C, al peſo di C A, il che ſi hauea da moſtrare. <emph.end type="italics"/></s></p>
</chap>
<chap id="N10205">
<p id="N10206" type="head">
<s id="N10208"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>III. </s></p><p id="N10210" type="main">
<s id="N10212">Se ad vn vna ſtatera ſiano appeſe due grauezze, e l' <lb/>interuallo delli ponti della ſoſpenſione ſi diuida nella <lb/>ragione delle grauezze: ſoſpeſa la ſtatera dal ponto del­<lb/>la diuiſione, ſta in equilibrio. </s></p><figure id="id.041.01.007.1.jpg" xlink:href="041/01/007/1.jpg"/>
<p id="N1021D" type="head">
<s id="N1021F"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N10225" type="main">
<s id="N10227"><emph type="italics"/>Sia la ſtatera A B: le grauezze in eſſa ſoſpeſe: C, &amp; D: la C, dal <lb/>ponto, A, &amp; la D, dal ponto, ‘B, &amp; in quellaragione che ha la gra­<lb/>uezza D, alla grauezza C, ſi diuida A B nel ponto E dico che ſoſpeſa <emph.end type="italics"/><pb xlink:href="041/01/008.jpg" pagenum="7"/><emph type="italics"/>la ſtatera nel ponto E, ſta in equilibrio. </s>
<s id="N10237">Si moſtra alla linea, B E, ta­<lb/>gliſi eguale la linea A F, dunque giunta communemente, F E, ſarà B <lb/>F, vguale ad A E, e perciò haurà B F, ad F A, l'iſteſſa ragione, che <lb/>D, a C. </s>
<s id="N1023F">facciaſi alla B F, vguale, B G, &amp; alla A F, vguale A H, <lb/>dunque ſe alla linea, G F, s'intenda applicato un corpo eguale di peſo <lb/>alla grauezza D, e tal corpo ſi allunghi nella isteſſa groſſezza fin ad H, <lb/>ſarà il corpo applicato ad F H, uguale di peſo a C: percio che hauendo <lb/>G F, ad F H, l'iſteſſa ragione che D, a C, e li corpi applicati l'iſteſ­<lb/>ſa delle linee: ſono perciò come la grauezza D alla C, coſi il cor­<lb/>po applicato ad F G, al corpo applicato ad H F: dunque mutando, ſo­<lb/>no anco proportionali: ma il corpo applicato a G F, è di peſo uguale al <lb/>D, dunque l'applicato ad F H è vguale di peſo a C: &amp; è delli due ap­<lb/>plicati, il commune punto di momento in E. </s>
<s id="N10253">Dunque delli D C inſie­<lb/>me pigliati il commun momento è nel ponto iſteſſo: &amp; percio la ſtatera <lb/>ſoſtenuta in E, ſta in equilibrio, ilche ſi hauea da moſtrare. <emph.end type="italics"/></s></p><p id="N1025B" type="head">
<s id="N1025D"><emph type="italics"/>Appendice. <emph.end type="italics"/> I. </s></p><p id="N10264" type="main">
<s id="N10266">Dal che è manifeſto che'l centro commune di due <lb/>peſi è il ponto che diuide l'interuallo de'centri loro, re­<lb/>ciprocamente. </s></p><p id="N1026C" type="head">
<s id="N1026E"><emph type="italics"/>Appendice. <emph.end type="italics"/> II. </s></p><p id="N10275" type="main">
<s id="N10277">E ſe due grauezze diuiſamente ſi appendono: che di­<lb/>uiſo l'interuallo nella ragione delle grauezze recipro­<lb/>camente: dette grauezze, fanno l'iſteſſo effetto nel <expan abbr="mo­mẽto">mo­<lb/>mento</expan>, che ſe in detto ponto <expan abbr="giuntamẽte">giuntamente</expan> fuſſero appeſe. </s></p>
</chap>
<chap id="N10287">
<p id="N10288" type="head">
<s id="N1028A"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>IIII. </s></p><p id="N10292" type="main">
<s id="N10294">Se due grauezze appeſe in due ponti facciano equi­<lb/>pondio: e di nuouo appeſe in due altri ponti facciano <pb xlink:href="041/01/009.jpg" pagenum="8"/>equipondio; l'interualli delle ſoſpenſioni mutate, ſono <lb/>proportionali con li peſi reciprocamente. </s></p><figure id="id.041.01.009.1.jpg" xlink:href="041/01/009/1.jpg"/>
<p id="N102A1" type="head">
<s id="N102A3"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N102A9" type="main">
<s id="N102AB"><emph type="italics"/>Sia la ſtatera A B: il ponto della ſoſpenſione C, li ponti onde ſono <lb/>appeſe le grauezze che fanno equipondio A &amp; B le grauezze appeſe <lb/>D &amp; E. </s>
<s id="N102B3">Quali di nuouo appeſe nelli ponti F &amp; G faccino equipondio: <lb/>dico che la F A interuallo delle due ſoſpenſioni di D, a B G, inter­<lb/>uallo delle <expan abbr="ſuſpẽſioni">ſuſpenſioni</expan> di E; ha quella ragione che la grauezza c alla gra­<lb/>uezza D. </s>
<s id="N102BF">Si moſtra perche D et E grauezze nella <expan abbr="ſuſpẽſion">ſuſpenſion</expan> prima han­<lb/>no equipondio: dunque la ragione della grauezza D ad E, è l'iſteſſa che <lb/>di B C a C A: e nella ſeconda ſuſpenſione la ragione di D ad E e l'iſteſ­<lb/>ſa che di G C a C F. </s>
<s id="N102CB">e perciò come B C à C A, coſi G C à C F, e per che <lb/>da due ſi togliono due altre nell'iſteſſa ragione, le reſtanti anco ſono nel­<lb/>l'iſteſſa ragione. </s>
<s id="N102D1">è dunque B G ad F A, come D ad E, ilche hauea da <lb/>moſtrarſi. <emph.end type="italics"/></s></p>
</chap>
<chap id="N102D7">
<p id="N102D8" type="head">
<s id="N102DA"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>V. </s></p><p id="N102E2" type="main">
<s id="N102E4">Se due grauezze facciano equipondio, e gionte ò tol­<lb/>te due altre grauezze facciano anco equipondio: le gion­<lb/>te ancora ò le tolte ſono nell'iſteſſa raggione. </s></p>
<pb xlink:href="041/01/010.jpg" pagenum="9"/>
<figure id="id.041.01.010.1.jpg" xlink:href="041/01/010/1.jpg"/>
<p id="N102F0" type="head">
<s id="N102F2"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N102F8" type="main">
<s id="N102FA"><emph type="italics"/>Sia la ſtatera A B: il ponto della ſuſpenſione C: le grauezze appe­<lb/>ſe D et E: che facciano equipondio: e di nouo aggiuntoui due altre F e G <lb/>facciano anco equipondio. </s>
<s id="N10302">dico che la grauezza F a G, ha la ragione <lb/>che D ad E: qual'è l'iſteſſa che di B C a C A. </s>
<s id="N10306">ſi moſtra perche D &amp; E, <lb/>fanno equipondio. </s>
<s id="N1030A">&amp; F e G fanno equipondio: perciò ſarà, come B C <lb/>à C A coſi D F ad E G e nell'iſteſſa era D ad E dunque le reſtanti F e G <lb/>ſono anco nell'iſteſſa ragione: e non altrimente che nella ſuppoſition del<lb/>la compoſta, ſi moſtra nella ſuppoſition delli reſidui. </s>
<s id="N10312">Haſſi dunque l'in­<lb/>tento. <emph.end type="italics"/></s></p>
</chap>
<chap id="N10318">
<p id="N10319" type="head">
<s id="N1031B"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>VI. </s></p><p id="N10323" type="main">
<s id="N10325">Date quante ſi voglia grauezze appeſe in vn'iſteſſa <lb/>ſtatera, ritrouare il ponto del momento commune. </s></p><p id="N10329" type="head">
<s id="N1032B"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N10331" type="main">
<s id="N10333"><emph type="italics"/>Sia la ſtatera A B dalli cui ponti A e B ſiano ſoſpeſe le grauezze C D <lb/>e ſiano in altri ponti ſoſpeſi altri peſi, come E nel ponto F: ſi cerca il pon­<lb/>to del momento commune. </s>
<s id="N1033B">diuidaſi la B A nella ragione di C a D reci­<lb/>procamente ſe dunque il detto punto uiene in F eſſendo F il ponto del <emph.end type="italics"/><pb xlink:href="041/01/011.jpg" pagenum="10"/><figure id="id.041.01.011.1.jpg" xlink:href="041/01/011/1.jpg"/><lb/><emph type="italics"/>momento delle C D pigliate inſieme, ſarà ponto di momento commu<lb/>ne delle grauezze C E D, tutte. </s>
<s id="N1034E">Et harraſſi l'intento. <emph.end type="italics"/></s></p><p id="N10352" type="main">
<s id="N10354"><emph type="italics"/>Ma ſe'l dato ponto caſchi altroue come in H, perche le grauezze <lb/>D, &amp; C appeſe in A e B fanno l'iſteſſo effetto che ſe giuntamente fuſſe­<lb/>ro appeſe in H: perciò ſe quella ragione che hà il compoſto di C D <lb/>ad E habbia reciprocamente F G a G H, ſarà G ponto di momento <lb/>commune di tutti. </s>
<s id="N10360">con l'iſteſſo ordine ſi ritrouerà il centro di quante <lb/>altre ſi uogliano, il che ſi hauea da trouare. <emph.end type="italics"/></s></p>
</chap>
<chap id="N10366">
<p id="N10367" type="head">
<s id="N10369"><emph type="italics"/>PROPOSITIONE<emph.end type="italics"/><lb/> VII. </s></p><p id="N10371" type="main">
<s id="N10373">Delle grauezze che fanno <expan abbr="equipõdio">equipondio</expan>, compoſte le ra­<lb/>gioni delle grauezze e delle diſtanze, li eſtremi termini <lb/>ſono eguali. </s></p><p id="N1037D" type="head">
<s id="N1037F"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N10385" type="main">
<s id="N10387"><emph type="italics"/>Sia la ſtatera A B il ponto del ſostenimento C le due grauezze che <lb/>fanno <expan abbr="equipõdio">equipondio</expan> D &amp; E: de quali la D ſia ſoſpeſa dal ponto A la E dal <expan abbr="põto">pon<lb/>to</expan> B: dico che compoſtala ragione della grauezza D ad E: e della <expan abbr="diſtãza">diſtanza</expan><lb/> A C a C B: cioè fatto che la <expan abbr="quãtità">quantità</expan> F a G ſia come la grauezza D ad E e <lb/>la quantità G ad H come la diſtanza A C alla C B, che F &amp; H <emph.end type="italics"/><pb xlink:href="041/01/012.jpg" pagenum="11"/><figure id="id.041.01.012.1.jpg" xlink:href="041/01/012/1.jpg"/><lb/><emph type="italics"/> eſtremi termini ſiano uguali. </s>
<s id="N103AF">ſi moſtra: perche A C a C B ſi è poſta co­<lb/>me G ad H: dunque riuoltando H à G, è come B C à C A. </s>
<s>e per l'e­<lb/>quipondio, come la diſtanza B C a C A coſi la grauezza D ad E, &amp; <lb/>come D ad E coſi ſi è pigliato F a G: dnnque F a G e come B C a C A, <lb/>e nell'iſteſſa ragione era H a G. </s>
<s id="N103B9">hanno dunque li due termini F et H l'i­<lb/>ſteſſa ragione al termine G. </s>
<s>e perciò li F &amp; H ſono eguali tra di loro: <lb/>il che ſi hauea da moſtrare. <emph.end type="italics"/></s></p>
</chap>
<chap id="N103C1">
<p id="N103C2" type="head">
<s id="N103C4"><emph type="italics"/>PROPOSITIONE<emph.end type="italics"/><lb/> VIII. </s></p><p id="N103CC" type="main">
<s id="N103CE">Li momenti delle grauezze uguali, appeſe in diſtan­<lb/>ze ineguali, hanno fra di loro la proportione che le di­<lb/>ſtanze. </s></p><p id="N103D4" type="head">
<s id="N103D6"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N103DC" type="main">
<s id="N103DE"><emph type="italics"/>Sia la ſtatera A B, il ponto del ſoſtenimento C, le grauezze uguali D <lb/>&amp; E. </s>
<s id="N103E4">de quali il D ſia appeſo in A, &amp; l'c in F. </s>
<s id="N103E6">dico che il momento <lb/>di D al momento di E, hà quella ragione che l'interuallo di A C all'­<lb/>interuallo di F C. </s>
<s id="N103EC">ſi moſtra, pigliato dall' altra parte del ſeſtem­<lb/>mento C, qual ſi uoglia ponto B: intendaſi in eſſa appeſe due grauezze, <emph.end type="italics"/><pb xlink:href="041/01/013.jpg" pagenum="12"/><figure id="id.041.01.013.1.jpg" xlink:href="041/01/013/1.jpg"/><lb/><emph type="italics"/>vna che faccia <expan abbr="equipōdio">equipondio</expan> a D &amp; ſia G: et vn'altra che faccia <expan abbr="equipōdio">equipondio</expan><lb/> ad E. </s>
<s id="N10406">&amp; ſia H. </s>
<s id="N10408">perche dunque G a D ha quella ragione che A C a C B <lb/>&amp; D ouero E ad H, hala ragione di B C a C F. </s>
<s id="N1040C">dunque di pari il pri­<lb/>mo termine A C all'ultimo F C, ha quella ragione, che il primo ter­<lb/>mine G, al terzo H. </s>
<s id="N10412">ſe dunque G ad H hal'iſteſſa ragione che la diſtan­<lb/>za A C alla diſtanza F C: &amp; il momento di G è uguale al momento <lb/>di D appeſo in A, &amp; il momento di H vguale al momento di E appeſo <lb/>in F. </s>
<s id="N1041A">dunque il momento di D al momento di E ha quella ragione che <lb/>la diſtanza A C alla diſtanza F C. </s>
<s id="N1041E">il che ſi hauea da moſtrare. <emph.end type="italics"/></s></p>
</chap>
<chap id="N10422">
<p id="N10423" type="head">
<s id="N10425"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>IX. </s></p><p id="N1042D" type="main">
<s id="N1042F">Li momenti delle grauezze ſoſpeſe in qual ſi uoglia <lb/>ponti della ſtatera, han tra di loro la ragion compoſta, <lb/>della ragion delle grauezze, e delle diſtanze. </s></p><p id="N10435" type="head">
<s id="N10437"><emph type="italics"/>Dimostratione. <emph.end type="italics"/></s></p><p id="N1043D" type="main">
<s id="N1043F"><emph type="italics"/>Sia la ſtatera A B il <expan abbr="pōto">ponto</expan> del <expan abbr="ſoſtenimẽto">ſoſtenimento</expan> C le grauezze appeſe D dal <lb/>
<expan abbr="pōto">ponto</expan> A, &amp; E dal ponto F. </s>
<s id="N10450">dico che la ragione del <expan abbr="momẽto">momento</expan> D al <expan abbr="momẽto">momen<lb/>to</expan> E, e compoſta di due ragioni cioè della ragione della grauezza D <lb/>alla grauezza E, e della diſtanza di A C alla F C. </s>
<s id="N1045E">ſi moſtra appenda <lb/>ſi da B la grauezza G che faccia equipondio. </s>
<s id="N10462">a D, &amp; il peſo H che fac­<emph.end type="italics"/><pb xlink:href="041/01/014.jpg" pagenum="13"/><figure id="id.041.01.014.1.jpg" xlink:href="041/01/014/1.jpg"/><lb/><emph type="italics"/>cia <expan abbr="equipōdio">equipondio</expan> all' E: dico prima che la grauezza G alla grauezza H G ha <lb/>la ragion compoſta, di D ad E, e di A C ad F C. </s>
<s id="N10477">per il che da moſtrare: in­<lb/>tendaſi nell' A ſoſpeſa la grauezza I uguale alla grauezza E, è manifeſto <lb/>che'l momento I al momento E, hà quella ragione che l'interuallo <lb/>A C all'interuallo F C come nel paſſato habbiamo moſtrato: &amp; il mo­<lb/>mento di D al momento d'I hà la ragione che la grauezza D alla gra­<lb/>uezza I: perche ſono da un'iſteſſo ponto ſoſpeſi. </s>
<s id="N10483">eſſendo dunque tre ter<lb/>mini in continua habitudine il momento D, il momento I, &amp; il <expan abbr="momẽ­to">momen­<lb/>to</expan> E: la ragione del primo termine al terzo è compoſta della ragione <lb/>di primo a ſecondo e della ragione di ſecondo a terzo: ma di primo <lb/>a ſecondo è di grauezza a grauezza: di ſecondo a terzo è d'interuallo <lb/>ad'interuallo. </s>
<s id="N10493">dunque, la ragione delli <expan abbr="momẽti">momenti</expan> di D ad E, che è l'iſteſſa <lb/>che della portione G alla portione H: è compoſta della ragione delle <lb/>grauezze e della ragione delle diſtanze. </s>
<s id="N1049D">Il che ſi hauea da moſtrare. <emph.end type="italics"/></s></p>
</chap>
<chap id="N104A1">
<p id="N104A2" type="head">
<s id="N104A4"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>X. </s></p><p id="N104AC" type="main">
<s id="N104AE">Data qual ſi uoglia grauezza, e li ponti della ſoſpen­<lb/>ſion della ſtatera, e della grauezza: e dato il peſo del <lb/>marco, ritrouare il luogo, oue detto marco faccia e­<lb/>quipondio con la grauezza data. </s></p>
<pb xlink:href="041/01/015.jpg" pagenum="14"/>
<figure id="id.041.01.015.1.jpg" xlink:href="041/01/015/1.jpg"/>
<p id="N104BC" type="head">
<s id="N104BE"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N104C4" type="main">
<s id="N104C6"><emph type="italics"/>Sia la ſtatera A B il ponto della ſoſpenſione C, la grauezza data D, <lb/>qual poniamo che ſi ſoſpenda in A: il marco dato di peſo E: ſi cerca il <lb/>ponto oue detto marco appeſo faccia equipondio. </s>
<s id="N104CE">per queſto: facciaſi <lb/>che quella ragione che hà il peſo E al peſo D, quella habbia la linea A <lb/>C a C F, dico che appeſo il marco in F fa equipondio, cioè che'l pon­<lb/>to del momento commune delle grauezze D &amp; e ſia il ponto della ſo­<lb/>ſpenſione C: il che è manifeſto, percioche ſono li peſi reciprochi al­<lb/>le diſtanze. </s>
<s id="N104DA">Haſſi dunque l'intento. <emph.end type="italics"/></s></p>
</chap>
<chap id="N104DE">
<p id="N104DF" type="head">
<s id="N104E1"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>XI. </s></p><p id="N104E9" type="main">
<s id="N104EB">Data una ſtatera, a cui ſia ugualmente applicato un <lb/>corpo, e data una grauezza ſoſpeſa da un dato ponto, <lb/>e dato il peſo del marco, ritrouare il ponto onde detto <lb/>marco ſoſpeſo faccia equipondio con la grauezza. </s></p><p id="N104F3" type="head">
<s id="N104F5"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N104FB" type="main">
<s id="N104FD"><emph type="italics"/>Sia la ſtatera A B il ponto del ſoſtenimento C, il corpo applicato <lb/>A D E B, la grauezza ſoſpeſa H I; il ponto onde la grauezza è appe­<lb/>ſa in A: il marco L, ſi cerca il ponto onde ſoſpeſo il marco, faccia e­<lb/>quipondio con H I, Per queſto: facciaſi alla linea A C uguale la C F,<emph.end type="italics"/><pb xlink:href="041/01/016.jpg" pagenum="15"/><figure id="id.041.01.016.1.jpg" xlink:href="041/01/016/1.jpg"/><lb/><emph type="italics"/>dunque il corpo D F applicato ad A F ſtà in equilibrio nel ponto della <lb/>ſoſpenſione C. </s>
<s>et diuiſa F B reſtante per metà nel ponto G: del reſtan­<lb/>te corpo F E applicato alla linea F B, ſarà G, il ponto di momento. </s>
<s id="N10518">ſe <lb/>dunque la ragione che hà C F ad F G, habbia la grauezza E F alla <lb/>parte del peſo I, ſtarà il corpo F E in <expan abbr="equipōdio">equipondio</expan> con I, e perciò ſe di nuo­<lb/>uo la ragione che hà, il marco al reſtante H habbia la parte de ſtate<lb/>ra A C, a C M, ſoſpeſo il marco L da M, farà equipondio <lb/>con H: &amp; il corpo F E facea equipondio con I: ſtarà dunque ogni coſa <lb/>in equilibrio. </s>
<s id="N1052A">ſi è dunque ritrouato il ponto M, onde ſoſpeſo il marco <lb/>faccia equipondio con la grauezza data. </s>
<s id="N1052E">Il che ſi hauea da ritrouare. <emph.end type="italics"/></s></p>
</chap>
<chap id="N10532">
<p id="N10533" type="head">
<s id="N10535"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>XII. </s></p><p id="N1053D" type="main">
<s id="N1053F">Fatta alla linea della ſtatera application di corpo, e <lb/>ſoſpeſe in eſſa più grauezze che ſoſtentino un peſo, ri­<lb/>trouare ciaſcuna grauezza quanto portion di peſo ſo­<lb/>ſtenti. </s></p><p id="N10547" type="head">
<s id="N10549"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N1054F" type="main">
<s id="N10551"><emph type="italics"/>Sia la linea della ſtatera A B il ponto del ſoſtentimento C &amp; alla <emph.end type="italics"/><pb xlink:href="041/01/017.jpg" pagenum="16"/><figure id="id.041.01.017.1.jpg" xlink:href="041/01/017/1.jpg"/><lb/><emph type="italics"/>linea A B ſia fatta application di corpo et in eſſa appeſe le grauezze D <lb/>E, F: D in A, E in G, F in H: e dette grauezze ſoſtentine il peſo I <lb/>K L M: il cui momento ſia nel ponto B: ſi cerca ciaſcuna di dette gra­<lb/>uezze D, E, F, quanta portione di peſo ſoſtenti. </s>
<s id="N10568">facciaſi per queſto alla <lb/>linea B C uguale la C N: e la reſtante N A ſi diuida in parti uguali nel <lb/>
<expan abbr="pōto">ponto</expan> O, e quella ragione che hà B C a C O quell'habbia il corpo della ſta­<lb/>tera applicato ad N A ad M: ſarà <expan abbr="dũque">dunque</expan>
<expan abbr="equipõderãte">equiponderante</expan>
<expan abbr="cõ">con</expan> M: c la par<lb/>te applicata ad N C è <expan abbr="equiponderãte">equiponderante</expan> alla applicata à B C: <expan abbr="dũque">dunque</expan> il cor­<lb/>po della ſtatera ſtà in <expan abbr="equipõdio">equipondio</expan> con la portione del peſo M: e le ragioni <lb/>delle grauezze D, E, F, e delle diſtanze A C, G C, H C, cioè la ragio­<lb/>ne della grauezza Dad F con la ragione della diſtanza A C a G C, <lb/>compongon la ragion di P a <expan abbr="q.">que</expan> &amp; la ragione della grauezza E ad F, <lb/>con la ragione della diſtanza G C ad H C, compongon la ragione <emph.end type="italics"/><pb xlink:href="041/01/018.jpg" pagenum="17"/><emph type="italics"/>di Q ad R, &amp; in quella ragione che ſono le tre quantità, P Q R, <lb/>poſte in continua habitudine, nella iſteſſa ſi diſtribuiſca il peſo I K L: <lb/>è manifeſto per quel che ſi è visto, che, D fa equiponderanza con I, lo <lb/>E co'l K, e lo F con lo L: ilche ſi cercaua. <emph.end type="italics"/></s></p>
</chap>
<chap id="N105A9">
<p id="N105AA" type="head">
<s id="N105AC"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>XIII. </s></p><p id="N105B4" type="main">
<s id="N105B6">La ſtatera di grauezze appeſe, che facciano equipon­<lb/>dio: quantunque dal ſito orizontale moſſa ſi ſtà. </s></p><figure id="id.041.01.018.1.jpg" xlink:href="041/01/018/1.jpg"/>
<p id="N105BD" type="head">
<s id="N105BF"><emph type="italics"/>Dimostratione. <emph.end type="italics"/></s></p><p id="N105C5" type="main">
<s id="N105C7"><emph type="italics"/>Sia la ſtatera nel ſito orizontale A B, il ponto della ſoſpenſione C, <lb/>li peſi e ſue centri D &amp; E, il centro commune di ambe le grauezze F; <lb/>e moſſa la statera del ſito orizontale, paſſi il ponto A in G, il B in H,<emph.end type="italics"/><pb xlink:href="041/01/019.jpg" pagenum="18"/><emph type="italics"/>ſi che habbia la ſtatera la poſitione di G C H: li peſi e ſui centri di, I e <lb/>K: dico, che la ſtatera G H ſtarà, e non ſi mouerà di ſito. </s>
<s id="N105D9">ſi moſtra <lb/>percioche eſſendo la grauezza I appeſa, inalzata, il centro ſuo gi­<lb/>rando verrà nella perpendicolare del ponto della ſoſpenſione: e perciò <lb/>I, verrà nella perpendicolare del ponto G e K del ponto H. </s>
<s id="N105E1">ſono <lb/>dunque, G I H K parallele. </s>
<s id="N105E5">e perche il centro commune de peſi, diui­<lb/>de nell'iſteſſa ragione la I K, &amp; la D E, eſſendo la ragione delli peſi <lb/>vn'iſteſſa, &amp; la C F nell'vna, e nell'altra ſoſpenſione perpendicolare, <lb/>e parallela, coſi alle A D E B, come alle G I, K H. </s>
<s id="N105ED">perciò diuidendo <lb/>C F perpendicolare ſimilmente la D E, &amp; la I K: ſarà il ponto F luo­<lb/>go del centro nell'vna, luogo anco di centro nell'altra. </s>
<s id="N105F3">eſſendo dunque <lb/>il centro del peſo commune nella perpendicolare della ſoſpenſione, ſta­<lb/>rà. </s>
<s id="N105F9">Ilche ſi hauea da moſtrare. <emph.end type="italics"/></s></p>
</chap>
<chap id="N105FD">
<p id="N105FE" type="head">
<s id="N10600"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>XV. </s></p><p id="N10608" type="main">
<s id="N1060A">La ſtatera di grauezze attaccate, che facciano equi­<lb/>pondio, ſe'l ponto della ſoſpenſione, non ſia nella linea <lb/>delli centri: moſſa dal ſito orizontale non ſtarà, ma ri­<lb/>tornarà nell'iſteſſo. </s></p><figure id="id.041.01.019.1.jpg" xlink:href="041/01/019/1.jpg"/>
<p id="N10615" type="head">
<s id="N10617"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N1061D" type="main">
<s id="N1061F"><emph type="italics"/>Sia la linea della ſtatera, che ſtia nel ſito horizontale A B, li pe­<lb/>ſi attaccati, &amp; li lor centri C e D, e diuidaſi G D ſecondo li peſi reci­<emph.end type="italics"/><pb xlink:href="041/01/020.jpg" pagenum="19"/><emph type="italics"/>procamente nel ponto E: è manifeſto che'l ponto E ſia il centro com­<lb/>mune di ambi li peſi, e che mentre la ſtatera ſta, che ſia detto centro <lb/>nella perpendicolare, che cala dal ponto F. </s>
<s id="N10631">perche dunque li peſi ſono <lb/>alla statera affiſſi, e non mutano li centri poſitura con la linea A B, e <lb/>ſempre fanno con eſſa angoli retti le C A, D B, E F, perciò moſſa <lb/>la ſtatera dal ſito horizontale, non ſarà E centro <expan abbr="cōmune">commune</expan> nella perpen­<lb/>dicolare della ſoſpenſione: ma girando vſcirà di detta perpendicolare, <lb/>e perciò la ſtatera non ſtarà, ſin che di nuouo il detto ponto non torne <lb/>nella perpendicolare. <emph.end type="italics"/></s></p><figure id="id.041.01.020.1.jpg" xlink:href="041/01/020/1.jpg"/>
<pb xlink:href="041/01/021.jpg" pagenum="20"/>
<p id="N1064B" type="head">
<s id="N1064D">VETTE, E <lb/>LEVA. </s></p><p id="N10651" type="head">
<s id="N10653"><emph type="italics"/>DEFINITION. <emph.end type="italics"/><lb/>I. </s></p><p id="N1065B" type="main">
<s id="N1065D">Vette diciamo la linea, che ſoſtiene grauezza, <lb/>qual ſia nelli ſue ponti eſtremi ſoſtenuta. </s></p><p id="N10661" type="head">
<s id="N10663"><emph type="italics"/>DEFINITION. <emph.end type="italics"/><lb/>II. </s></p><p id="N1066B" type="main">
<s id="N1066D">Et altrimente, vette motiua e leua, la linea che ſo­<lb/>ſtenga grauezza, ſtabilita in vn ponto che ſotto leua <lb/>diciamo, &amp; in vn'altro ponto da poſſanza, o moſſa, o <lb/>ſoſtenuta. </s></p><p id="N10675" type="head">
<s id="N10677"><emph type="italics"/>POSITION. <emph.end type="italics"/><lb/>I. </s></p><p id="N1067F" type="main">
<s id="N10681">Miſuriamo la poſſanza con vna grauezza equiualen­<lb/>te, o appeſa nell'iſteſſo ponto della poſſanza, o nell'al­<lb/>tro ponto egualmente dal ſottoleua diſcoſto. </s></p><p id="N10687" type="head">
<s id="N10689"><emph type="italics"/>POSITION. <emph.end type="italics"/><lb/>II. </s></p><p id="N10691" type="main">
<s id="N10693">Ciaſcuna poſſanza in quanto ſoſtiene, eſſere egua­<lb/>le al peſo ſoſtenuto. </s></p><figure id="id.041.01.021.1.jpg" xlink:href="041/01/021/1.jpg"/>
<pb xlink:href="041/01/022.jpg" pagenum="21"/>
<p id="N1069D" type="head">
<s id="N1069F"><emph type="italics"/>PROPOSITION. <emph.end type="italics"/><lb/>I. </s></p><p id="N106A7" type="main">
<s id="N106A9">S'il ſottoleua ſtia tra la grauezza, e la poſſanza che <lb/>ſoſtenga detta grauezza; ſarà tra la poſſanza, &amp; il pe­<lb/>ſo la ragione, che è tra le parti della leua, reciprocamen­<lb/>te. </s></p><figure id="id.041.01.022.1.jpg" xlink:href="041/01/022/1.jpg"/>
<p id="N106B4" type="head">
<s id="N106B6"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N106BC" type="main">
<s id="N106BE"><emph type="italics"/>Sia la linea A B, il ponto del ſottoleua C, la grauezza D ſoste­<lb/>nuta nel ponto della leua A; la poſſanza che ſoſtenga detta grauez­<lb/>za in B: dico che la poſſanza B al peſo D, ha quella ragione che ha <lb/>la parte di leua A C alla C B, qual è ragion reciproca. </s>
<s id="N106C8">ſi moſtra: inten­<lb/>daſi attaccato in B il peſo che faccia equipondio con D: è manifeſto che <lb/>detto peſo E ſia equiualente alla forza B, ma il peſo E al peſo D ha la <lb/>ragione che A C a C B, che è la ragione reciproca di grauezza, e di­<lb/>ſtanze: dunque, la potenza ancora haue l'iſteſſa ragione. </s>
<s id="N106D2">ilche ſi ha­<lb/>uea da moſtrare. <emph.end type="italics"/></s></p><p id="N106D8" type="head">
<s id="N106DA"><emph type="italics"/>PROPOSITION. <emph.end type="italics"/><lb/>II. </s></p><p id="N106E2" type="main">
<s id="N106E4">Se due potenze ſoſtentino vna grauezza con vn vet­<lb/>te, ciaſcuna ſoſtentarà la ſua portione, ſecondo l'inter­<lb/>uallo del peſo dalle potenze, pigliato reciprocamente. </s></p>
<pb xlink:href="041/01/023.jpg" pagenum="22"/>
<figure id="id.041.01.023.1.jpg" xlink:href="041/01/023/1.jpg"/>
<p id="N106F0" type="head">
<s id="N106F2"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N106F8" type="main">
<s id="N106FA"><emph type="italics"/>Sia il vette A B, dal cui ponto D, penda il peſo C: le potenze che <lb/>ſoſtengono dette grauezze ſiano A &amp; B: dico che'l B, e lo A ſoſten­<lb/>tano portioni proportionali all'interualli reciprocamente: cio è che <lb/>quella ragione c'ha l'interuallo, B D, a D A, quella hàbbia la por­<lb/>tione ſoſtentata dall' A, alla portione ſoſtentata dal B, ſi dimoſtra: <lb/>tagliſi ad A D uguale B E, accoppiata dunque communemente la D <lb/>E, ſarà A E uguale a B D: aggiungaſi all' A e la A G, che le ſia egua­<lb/>le, &amp; ad E B la B F che ſimilmente le ſia eguale. </s>
<s id="N1070C">ſarà di tutta la G F, <lb/>il ponto mezzano D, &amp; della G E, il ponto mezzano A, &amp; della E <lb/>F, il ponto mezzano B. </s>
<s id="N10712">applicata dunque a tutta la G F, una grauez­<lb/>za che ſia uguale a C, ſarà di detta grauezza il ponto di momento in D <lb/>&amp; ſarà equiualente nella ſua operatione alla grauezza C, &amp; di eſſa <lb/>la parte applicata a G E ha il ſuo momento in A, c la parte applica­<lb/>ta ad E ha il ſuo momento in B. </s>
<s id="N1071C">dunque della grauezza applicata <lb/>la potenza A, ne ſoſtentarà la portione applicata a G E: e la potenza <lb/>B, la portione applicata ad E F. </s>
<s id="N10722">Ma G E ad E F, ha la ragione che <lb/>l'interuallo B D, a D A che è reciproca. </s>
<s id="N10726">dunque le potenze ſoſtenta­<lb/>no le portioni de'peſi proportionali, reciprocamente pigliate con l'inter<lb/>ualli. </s>
<s id="N1072C">ilche ſi hauea da moſtrare. <emph.end type="italics"/></s></p>
<pb xlink:href="041/01/024.jpg" pagenum="23"/>
</chap>
<chap id="N10733">
<p id="N10734" type="head">
<s id="N10736"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>III. </s></p><p id="N1073E" type="main">
<s id="N10740">Se il ſottoleua ſia fuori della grauezza, e della poſ­<lb/>ſanza, ſarà la ragion della poſſanza alla grauezza l'iſteſ<lb/>ſa, che dell'interualli da eſse al ſottoleua <expan abbr="reciprocamẽ­te">reciprocamen­<lb/>te</expan> pigliati </s></p><figure id="id.041.01.024.1.jpg" xlink:href="041/01/024/1.jpg"/>
<p id="N1074F" type="head">
<s id="N10751"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N10757" type="main">
<s id="N10759"><emph type="italics"/>Sia la leua A B il ſotto leua A, la grauezza C, il ſuo momento in <lb/>D, la poſſanza che ſoſtiene in B: dico che la poſſanza alla grauezza <lb/>ha la ragione, che D A ad A B, che è la ragion delle diſtanze piglia­<lb/>te dal ſottoleua reciprocamente: ſi moſtra: perche il peſo C, e ſoſten­<lb/>tato dalla leua B A, e la leua è ſoſtentata in due ponti B &amp; A. </s>
<s id="N10765">dunque <lb/>il peſo è ſoſtentato dalle potenze in B &amp; A compartitamente, cioe
<lb/>la poſſanza B ſoſtenta tal portion di peſo, qual'è la diſtanza A D di A <lb/>B, &amp; A, tal portione qual'è D B, di B A, e perche la poſſanza ſo­<lb/>ſtenente è uguale al peſo che ſoſtiene, ſono ambe le poſſanze B &amp; A <lb/>giuntamente pigliate uguali al peſo E; e la portione ſoſtentata da B: <lb/>al tutto harrà quella ragione che la portion della leua D A a tutta <lb/>la leua A B. </s>
<s id="N10776">qual è l'iſteſſa che della diſtanza della grauezza, alla di­<lb/>ſtanza della potenza. </s>
<s id="N1077A">ſi ha dunque l'intento. <emph.end type="italics"/></s></p>
<pb xlink:href="041/01/025.jpg" pagenum="24"/>
</chap>
<chap id="N10781">
<p id="N10782" type="head">
<s id="N10784"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>IV. </s></p><p id="N1078C" type="main">
<s id="N1078E">Se vna grauezza ſia con vna leua ſoſtenuta da due <lb/>ponti; &amp; accreſciuta la leua dall altra parte ſi appenda <lb/>grauezza equiponderante, &amp; ſi traſmuti in ſtatera: ſo­<lb/>itentarà il ſoſtenimento in tal commutatione peſo mag<lb/>giore, quale al peſo di prima ſoſtenuto, ha ragione com<lb/>poſta della ragione delle portioni di tutta la linea accre<lb/>ſciuta communicanti, alle portioni interuallate: fat­<lb/>te le due diuiſioni al ponto del ſottoleua, &amp; al ponto <lb/>del primo momento. </s></p><figure id="id.041.01.025.1.jpg" xlink:href="041/01/025/1.jpg"/>
<p id="N107A3" type="head">
<s id="N107A5"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N107AB" type="main">
<s id="N107AD"><emph type="italics"/>Sia la leua A B, il ſottoleua in A: la grauezza ſoſtenuta in C, la <lb/>poſſanza che'l ſoſtiene in B. </s>
<s>&amp; allungata la B A in vn D, appenda­<lb/>ſi in D, vna grauezza che ſoſtenti la grauezza C. </s>
<s id="N107B5">dico che in queſta <lb/>commutatione il ſottoleua A ſoſtenti peſo maggiore, &amp; che il peſo <lb/>ſoſtenuto in detta commutatione, al peſo ſoſtenuto di prima, ha la ra­<lb/>gion compoſta delle D C, A D, parti communicanti, alle D A, a C <lb/>B, parti interuallate. </s>
<s id="N107BF">ſi moſtra: perche la parte del peſo ſoſtenuto da <lb/>A, a tutto il peſo C, ha la ragione, che B C a B A: &amp;. </s>
<s id="N107C3">il peſo C, ad <lb/>ambi li peſi C &amp; D, ha la ragione che D A a D C, ma la ragione del­<emph.end type="italics"/><pb xlink:href="041/01/026.jpg" pagenum="25"/><emph type="italics"/>la portione ſoſtenuta da A, alla grauezza C, &amp; di C, ad ambe CD, ſot<lb/>trattone il termine mezzano, compongono la ragione della portione ſoſte <lb/>nuta da A, ad ambe le C D, &amp; la ragione di B C a BA, &amp; di D A a D <lb/>C, fanno la ragione compoſta delle parti communicanti alle interuallate. </s><lb/>
<s id="N107D6">Haſſi dunque l'intento: che'l peſo di prima ſoſtenuto, al peſo ſoſtenuto <lb/>dopo la commutatione, ha la ragion compoſta delle parti interuallate alle <lb/>communicanti. </s>
<s id="N107DC">Ilche ſi hauea da moſtrare. <emph.end type="italics"/></s></p>
</chap>
<chap id="N107E0">
<p id="N107E1" type="head">
<s id="N107E3"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>V. </s></p><p id="N107EB" type="main">
<s id="N107ED">Date nell' eſtremità del vette due poſsanze c'habbia­<lb/>no qualſiuoglia ragione tra di loro; e dato vn peſo, a det­<lb/>te poſſanze giuntamente pigliate vguale, ritrouare il <lb/>ponto del vette, onde il dato peſo ſoſpeſo, ſia da det<lb/>te poſſanze ſoſtenuto. </s></p><figure id="id.041.01.026.1.jpg" xlink:href="041/01/026/1.jpg"/>
<p id="N107FA" type="head">
<s id="N107FC"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N10802" type="main">
<s id="N10804"><emph type="italics"/>Sia il vette AB: le poſſanze nelli ponti A e B, c'habbiano tradi lo­<lb/>ro qualſiuoglia ragione: &amp; il peſo ad ambe poſſanze giuntamente pi­<lb/>gliate vguale ſia C: ſi cerca il ponto, onde detto peſo ſia da dette <expan abbr="poßãanze">poßan<lb/>ze</expan> ſoſtenuto. </s>
<s id="N10812">per il che dico: che ſe in quella ragione, c' ha la poſſan­<emph.end type="italics"/><pb xlink:href="041/01/027.jpg" pagenum="26"/><emph type="italics"/>za B, ſi diuida la vette AB in D, e ſia come la poſſanza A alla B: così, <lb/>la portione di vette B D a D A: dico che poſto il peſo C, in D: ſarà, <lb/>ſoſtenuto da dette poſſanze: percioche grauando il peſo nelli ponti B: &amp; <lb/>A, che ſoſtentano compartitamente, ſecondo la ragion di BD a DA: <lb/>&amp; hauendo la portion che graua in A, alla portion che graua in B, la <lb/>ragion che B D a D A: qual'è l'iſteſſa che della poſſanza A alla poſſanza <lb/>B: dunque la portione che graua in, A alla portione che graua in B, <lb/>e come la poſſanza A, alla B: e <expan abbr="permutãdo">permutando</expan> la portion che graua in A, a <lb/>la poſſanza A, ſarà come la portione che graua in B alla poſſanza B, <lb/>e componendo li antecedenti, tutto il peſo C, ad ambe le poſſanze giun<lb/>te, harrà l'iſteſſa ragione che vna advna: ma il peſo tutto C, è vgua­<lb/>le ad ambe le poſſanze giuntamente pigliate: dunque diuiſamente le <lb/>portioni, ciaſcuna alla poſſanza oue graua, ſarà vguale: e percio ſa­<lb/>rà del peſo ſoſtenuto, la portione che graua in A, vguale alla poſſanza <lb/>in A: e la portione che graua in B, vguale alla pòſſanza in B: e percio <lb/>le poſſanze ſoſtentaranno il detto peſo nel ponto D. </s>
<s id="N1083E">Il che ſi hauea da <lb/>moſtrare,<emph.end type="italics"/></s></p><p id="N10844" type="head">
<s id="N10846"><emph type="italics"/>Appendice. <emph.end type="italics"/></s></p><p id="N1084C" type="main">
<s id="N1084E">Et è manifeſto che in ogni altro ponto del detto vet<lb/>te, il peſo non ſarà ſoſtenuto, ma aggrauerà più l'vna ò <lb/>l'altra poſſanza, verſo oue ſarà portato. </s></p>
</chap>
<chap id="N10854">
<p id="N10855" type="head">
<s id="N10857"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>VI. </s></p><p id="N1085F" type="main">
<s id="N10861">Se una leua ſia inalzata, o baſſata ſotto l'orizonte: <lb/>&amp; da un ponto fuori di eſſa, ſi tireranno due perpendi­<lb/>colari, l'vna ad eſſa leua, e l'altra all'orizonte: faran<lb/>no le due perpendicolari angolo tra di loro, vguale all' <lb/>angolo della leua con l'orizonte. </s></p>
<pb xlink:href="041/01/028.jpg" pagenum="27"/>
<figure id="id.041.01.028.1.jpg" xlink:href="041/01/028/1.jpg"/>
<p id="N10871" type="head">
<s id="N10873"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N10879" type="main">
<s id="N1087B"><emph type="italics"/>Sia la linea orizontale A B, la leua ſopra di eſſa inalzata o deſpreſ­<lb/>ſa A C. </s>
<s>il ponto fuori della leua E: da cui ſi tirino due perpendicolari <lb/>l'vna alla leua DE, l'altra all'orizonte D F, che ſeghi la leua in F, &amp; <lb/>la linea orizontale in G. </s>
<s id="N10885">dico che l'angolo fatto dalle due D E, D F <lb/>ſia vguale all'angolo fatto, dalle due A B, A C: ſi moſtra: percioche <lb/>le due A C, D G, ſi ſegano nel ponto F, ſaranno l'angoli A F G, et D <lb/>F E, d'incontro vguali: e gli angoli ad E &amp; G ſono retti: dunque il tri­<lb/>angolo D F E, è equiangolo al triangolo A F G, e l'angolo F D E, v­<lb/>guale a l'angolo F A G. </s>
<s id="N10891">Il che ſi hauea da mòſtrare. <emph.end type="italics"/></s></p><p id="N10895" type="head">
<s id="N10897"><emph type="italics"/>Appendice,<emph.end type="italics"/></s></p><p id="N1089D" type="main">
<s id="N1089F">Et è manifeſto che eſſendo detto ponto di ſopra la li<lb/>nea della leua inalzata, e di ſotto della leua baſſata; ſe­<lb/>cherà detta linea in ponto più dalla poſſanza lontano. </s><lb/>
<s id="N108A6">e per <expan abbr="cõtrario">contrario</expan> pigliandoſi detto ponto, o ſotto dell'alza­<lb/>tà, o ſopra della baſſata, ſegherà in ponti più à detta pos­<lb/>ſanza vicini. </s></p>
<pb xlink:href="041/01/029.jpg" pagenum="28"/>
</chap>
<chap id="N108B3">
<p id="N108B4" type="head">
<s id="N108B6"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>VII. </s></p><p id="N108BE" type="main">
<s id="N108C0">Se'l centro del peſo attaccato ad eſſa leua ſia ſopra <lb/>della leua, inalzata la leua, la poſſanza ſoſtentarà minor <lb/>peſo. </s></p><figure id="id.041.01.029.1.jpg" xlink:href="041/01/029/1.jpg"/>
<p id="N108C9" type="head">
<s id="N108CB"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N108D1" type="main">
<s id="N108D3"><emph type="italics"/>Sia la leua A B, a cui ſia attaccata vna grauezza, il cui centro ſia <lb/>C: &amp; intendaſi detta leua in ſito dall'orizonte eleuato: dico che la po­<lb/>tenza B, ſoſtenta del peſo della grauezza minor portione, che nel ſito <lb/>orizontale. </s>
<s id="N108DD">ſi moſtra: tirinſi dal ponto C linee, l'vna perpendicolare <lb/>alla leua che ſia C D, &amp; l'altra perpendicolare all'orizonte, che <lb/>ſia C E, che ſeghi la leua nel ponto E: è manifeſto che'l detto ponto <lb/>ſarà più diſcoſto dalla poſſanza, e più vicino al ponto del ſottoleua. </s>
<s id="N108E5">ſe <lb/>dunque per lo ponto C, ſi tiri la linea G C F, parallela all'orizonte, &amp; <lb/>per li ponti B &amp; A, le linee B F, A G, perpendicolari <expan abbr="all'orizõte">all'orizonte</expan> è mani <lb/>feſto, che l'iſteſſo effetto fa la poſſanza in F che ſe fuſſe in B, e lo ſoſtegno <lb/>in A l'iſteſſo che ſe fuſſe in C: percioche ciaſcun momento opera ſecon<lb/>da la ſua perpendicolare: perche dunque poſta la poſſanza in F, e lo ſo­<emph.end type="italics"/><pb xlink:href="041/01/030.jpg" pagenum="29"/><emph type="italics"/>ſtegno in G, la poſſanza F, ſoſtiene tal portione di tutto il peſo, qual <lb/>portione è G C, di G F: e qual'è G C, di tutta G F, tal'è A E di tutta <lb/>A B, perche le A G, C E, B F, ſono parallele: ſoſtenta dunque la poſ­<lb/>ſanza B, del peſo tal portione, qual'è A E di tutta A B: ſe dunque <lb/>A E è minor portione di A B, che la A D, dell'iſteſſa A B: la poſſan<lb/>za con la leua inalzata il cui centro del peſo è ſopra, ſoſtenta minor <lb/>portione che nel ſito orizontale. </s>
<s id="N10909">Il che ſi hauea da moſtrare. <emph.end type="italics"/></s></p><p id="N1090D" type="head">
<s id="N1090F"><emph type="italics"/>Appendice. </s>
<s id="N10913">I. <emph.end type="italics"/></s></p><p id="N10917" type="main">
<s id="N10919">E per l'iſteſſo mezzo ſi moſtrerà che quanto più la le <lb/>ua s'inalza, tanto minor peſo ſoſtiene. </s></p><p id="N1091D" type="head">
<s id="N1091F"><emph type="italics"/>Appendice. </s>
<s id="N10923">II. <emph.end type="italics"/></s></p><p id="N10927" type="main">
<s id="N10929">E che poſto il centro della grauezza ſotto la leua, <lb/>quanto più s'inalzi, magior portione di peſo ſoſtenga. </s></p><p id="N1092D" type="head">
<s id="N1092F"><emph type="italics"/>Appendice. </s>
<s id="N10933">III. <emph.end type="italics"/></s></p><p id="N10937" type="main">
<s id="N10939">E che nelle leue baſſate ſotto l'orizonte, auuenga a <lb/>contrario. </s></p>
</chap>
<chap id="N1093D">
<p id="N1093E" type="head">
<s id="N10940"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>VIII. </s></p><p id="N10948" type="main">
<s id="N1094A">Dato nella leua il ponto di momento di una grauez­<lb/>za, e data qualſivoglia ragione di poſſanza a grauez­<lb/>za, ritrouar nella leua il ponto, oue la data poſſanza ſo<lb/>ſtenga la data grauezza. </s></p>
<pb xlink:href="041/01/031.jpg" pagenum="30"/>
<figure id="id.041.01.031.1.jpg" xlink:href="041/01/031/1.jpg"/>
<p id="N10958" type="head">
<s id="N1095A"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N10960" type="main">
<s id="N10962"><emph type="italics"/>Sia nella leua A B, il ponto del ſottoleua in A: il ponto di momen­<lb/>to della data grauezza in C. </s>
<s>et la ragion della poſſanza data alla grauez<lb/>za, come di E a D: ſi cerca nella leua il ponto, oue poſta la data poſ­<lb/>ſanza ſoſtenga la data grauezza. </s>
<s id="N1096C">per queſto: facciaſi come E a D, così <lb/>A C ad A F: &amp; intendaſi la poſſanza in F. </s>
<s id="N10970">dico che detta poſſanza in <lb/>F ſoſtiene la grauezza in C. </s>
<s id="N10974">ſi moſtra: percioche eſſendo la ragion del­<lb/>la poſſanza alla grauezza come E a D, e la ragion dell'interuallo del<lb/>la grauezza A C, all'interuallo della poſſanza A F, l'iſteſſa reciproca <lb/>mente: ſoſtentarà dunque la data poſſanza in F, la grauezza in C. </s>
<s id="N1097C">Il <lb/>che ſi cercaua. <emph.end type="italics"/></s></p><p id="N10982" type="head">
<s id="N10984"><emph type="italics"/>Appendice. <emph.end type="italics"/></s></p><p id="N1098A" type="main">
<s id="N1098C">Et è manifeſto che in qual ſi uoglia altro ponto oltre <lb/>del termine del ſoſtenimento, la data poſſanza mouerà <lb/>la data grauezza: e tanto più facilmente quanto più ſi <lb/>ſcoſtarà. </s></p><figure id="id.041.01.031.2.jpg" xlink:href="041/01/031/2.jpg"/>
<pb xlink:href="041/01/032.jpg" pagenum="31"/>
<p id="N1099A" type="head">
<s id="N1099C">RAGGI NELL <lb/>ASSE. </s></p><p id="N109A0" type="head">
<s id="N109A2"><emph type="italics"/>SVPPOSITIONE. <emph.end type="italics"/></s></p><p id="N109A8" type="main">
<s id="N109AA">Svpponiamo, in vno iſteſſo aſſe, due rag<lb/>gi c'habbiano nelli ſuoi ſtremi li centri de peſi. </s></p><p id="N109AE" type="main">
<s id="N109B0">E detti raggi, o in vna pianezza, e che non facciano <lb/>angolo, o in due, e che facciano angolo. </s></p><p id="N109B4" type="head">
<s id="N109B6"><emph type="italics"/>POSITIONE. <emph.end type="italics"/></s></p><p id="N109BC" type="main">
<s id="N109BE">Pigliamo, il momento di ciaſcun peſo, ſecondo il pon<lb/>to, oue la perpendicolare del momento taglia la linea <lb/>orizontale, che paſſa per l'aſſe. </s></p><figure id="id.041.01.032.1.jpg" xlink:href="041/01/032/1.jpg"/>
</chap>
<chap id="N109C7">
<p id="N109C8" type="head">
<s id="N109CA"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>I. </s></p><p id="N109D2" type="main">
<s id="N109D4">Delle grauezze poſte in raggi che non fanno tra di <lb/>loro angolo, in qualunque ſito poſte, li momenti tra di <lb/>loro hanno l'iſteſſa ragione. </s></p><p id="N109DA" type="head">
<s id="N109DC"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N109E2" type="main">
<s id="N109E4"><emph type="italics"/>Sial'aſſe A, a cui ſiano affiſſi li raggi A B, A C, quali s'intenda­<emph.end type="italics"/><pb xlink:href="041/01/033.jpg" pagenum="32"/><figure id="id.041.01.033.1.jpg" xlink:href="041/01/033/1.jpg"/><lb/><emph type="italics"/>no eſſere nel ſito orizontale, &amp; mouaſi dal detto ſito, sì che il B uen<lb/>ga in D, &amp; il C venga in E: dico che li momenti delle grauezze in det<lb/>ti raggi quantunque moſſi di ſito, ſiano nell'iſteſſa ragione tra di loro. </s><lb/>
<s id="N109FA">ſi moſtra: tiriſi per D la perpendicolare D F &amp; per E la perpendicola <lb/>re E G; perche dunque F A ad A G, ha la ragione che D A ad A E, <lb/>perciò che ſono D F, E G, parallele: ma come D A ad A E, così B A ad <lb/>A C: perche ſono l'iſteſſi raggi, come dunque B A ad A C, così F A <lb/>ad A G: e perche la ragion delli momenti e compoſta della ragion delle <lb/>grauezze, e della ragion delle diſtanze dal centro: ma la ragione delle <lb/>grauezze è l'iſteſſa: e la ragione delle <expan abbr="diſtãze">diſtanze</expan> è l'iſteſſa: dunque la ragion <lb/>di ambe compoſte, è anco l'iſteſſa. </s>
<s id="N10A0E">Il che ſi hauea da moſtrare. <emph.end type="italics"/></s></p>
<pb xlink:href="041/01/034.jpg" pagenum="33"/>
</chap>
<chap id="N10A15">
<p id="N10A16" type="head">
<s id="N10A18"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>II. </s></p><p id="N10A20" type="main">
<s id="N10A22">Date qual ſi uoglia due grauezze, nelli raggi che fac­<lb/>ciano angolo dato, ritrouar nelle loro circolationi, pon­<lb/>ti oue facciano equipondio. </s></p><figure id="id.041.01.034.1.jpg" xlink:href="041/01/034/1.jpg"/>
<p id="N10A2B" type="head">
<s id="N10A2D"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N10A33" type="main">
<s id="N10A35"><emph type="italics"/>Sia l'aſſe A: li raggi che facciano <expan abbr="ãgolo">angolo</expan> dato A C, B A: &amp; intendaſi <expan abbr="nel­li">nel­<lb/>li</expan> ponti B e C, eſſer li <expan abbr="cẽtri">centri</expan> delle grauezze: &amp; le circonferenze che det­<lb/>ti ponti girando attorno fanno, ſiano E B, C F: ſi cercano in dette cir­<emph.end type="italics"/><pb xlink:href="041/01/035.jpg" pagenum="34"/><emph type="italics"/>conferenze li ponti, oue eſſendo dette grauezze, facciano equipondio. </s><lb/>
<s id="N10A52">Diuidaſi la B C interuallo de centri, ſiche qual ragione ha la grauezza, <lb/>B, alla C, tal habbia la linea C D alla, D B: e tiriſi A D: e tirata <lb/>per A, la A E B perpendicolare all'Orizonte, facciaſi all'angolo D A <lb/>B, vguale lo E A G: &amp; allo D A C, vguale E A H: dico che'l ponto <lb/>G, è oue portato il B, &amp; H, oue portato il C, fanno equipondio. </s>
<s id="N10A5C">E prima <lb/>che portato il B in G, venga il C in H, è manifeſto: percioche l'ango <lb/>B A C è vguale al G A H: e per l'iſteſſa ragione, è manifeſto che nell' <lb/>iſteſſo tempo il ponto D, ſia nella A E. </s>
<s id="N10A64">ma il <expan abbr="põto">ponto</expan> D è il centro commu­<lb/>ne di peſo di dette due grauezze. </s>
<s id="N10A6C">E dunque il centro commune nel <lb/>la perpendicolare del ſoſtenimento: e perciò le grauezze ſtanno. </s>
<s id="N10A70">Jl che <lb/>ſi cercaua. <emph.end type="italics"/></s></p><p id="N10A76" type="head">
<s id="N10A78"><emph type="italics"/>Appendice. </s>
<s id="N10A7C">I. <emph.end type="italics"/></s></p><p id="N10A80" type="main">
<s id="N10A82">Et è manifeſto che nelli due ponti, oppoſti alli ritroua <lb/>ti, facciano equipondio: &amp; non altroue: percioche in o­<lb/>gni altra poſitura oltre di dette due, il centro commune <lb/>e fuori del perpendicolo. </s></p><p id="N10A8A" type="head">
<s id="N10A8C"><emph type="italics"/>Appendice. </s>
<s id="N10A90">II. <emph.end type="italics"/></s></p><p id="N10A94" type="main">
<s id="N10A96">Et è manifeſto che nell'arco ſotto il ponto dell'equi<lb/>pondio la grauezza ha momento maggiore: e nell'arco <lb/>ſopra il ponto dell'equipondio ha momento minore. </s></p>
</chap>
<chap id="N10A9C">
<p id="N10A9D" type="head">
<s id="N10A9F"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>I. </s></p><p id="N10AA7" type="main">
<s id="N10AA9">Dàte qual ſi uoglia due grauezze nelli dati raggi, che <lb/>fanno dato angolo: ritrouar nelle loro circolationi, pon­<pb xlink:href="041/01/036.jpg" pagenum="35"/>ti oue il momento dell'uno, al <expan abbr="momẽto">momento</expan> dell'altro habbia <lb/>qual ſi voglia data ragione. </s></p><figure id="id.041.01.036.1.jpg" xlink:href="041/01/036/1.jpg"/>
<p id="N10ABA" type="head">
<s id="N10ABC"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N10AC2" type="main">
<s id="N10AC4"><emph type="italics"/>Siano le date grauezze A &amp; B: li raggi AC, BC, fiſſi nell'aſſe C: <lb/>che facciano dato <expan abbr="ãgolo">angolo</expan>: e la circolation di A ſia, AD: di B ſia B E. </s>
<s>e <lb/>la data qualſiuoglia ragione ſia di F a G: ſi cercano nella circolatione DA <lb/>e nella BE, ponti oue habbian li momenti di A e B, ragion di F a G. </s>
<s id="N10AD2">In­<lb/>tendaſi nella ragion di A a B, la quantità F ad H. </s>
<s id="N10AD6">e nella reſtante ra­<lb/>gione di H a G, ſi diuida A B in L. </s>
<s id="N10ADA">&amp; all'angolo L C A facciaſi vgua­<emph.end type="italics"/><pb xlink:href="041/01/037.jpg" pagenum="36"/><emph type="italics"/>le il D C M, &amp; allo L C B eguale il DCN: èmanifeſto, che portato A in <lb/>M: B verrà in N. </s>
<s id="N10AE6">&amp; il ponto L nella perpendicolare C D. </s>
<s id="N10AE8">e ſe per il <lb/>ponto C ſi tiri la P C Q parallela all'Orizonte: e dalli ponti M &amp; N ſi <lb/>tirino a queſta, perpendicolari le MQ NP: ſarà il momento della <lb/>grauezza in M, al momento della grauezza in N di ragion compo <lb/>ſta della grauezza A alla grauezza B, e della distanza Q C, alla CP, <lb/>che è l'iſteſſa che di A L ad L B.percioche queſta è l'iſteſſa che di M O ad <lb/>O N: cioè della compoſta delle ragioni di F ad H, e di H a G: ciò è di F a <lb/>G. </s>
<s id="N10AF8">
<expan abbr="harrãno">harranno</expan> dunque li <expan abbr="momẽti">momenti</expan> di A &amp; B, mentre ſiano poſti nelli ponti <lb/>M &amp; N la ragion data di F a G. </s>
<s id="N10B03">Il che ſi cercaua. <emph.end type="italics"/></s></p><p id="N10B07" type="head">
<s id="N10B09"><emph type="italics"/>Appendice. <emph.end type="italics"/></s></p><p id="N10B0F" type="main">
<s id="N10B11">Et è manifeſto che prodotte le linee del centro nelli <lb/>ponti oppoſti delle dette circonferenze, hauranno iui li <lb/>momenti delle date grauezze l'iſteſſa ragione: e non <lb/>altroue. </s></p><figure id="id.041.01.037.1.jpg" xlink:href="041/01/037/1.jpg"/>
<pb xlink:href="041/01/038.jpg" pagenum="37"/>
<p id="N10B1F" type="head">
<s id="N10B21">MOMENTI <lb/>CENTRALI</s></p><p id="N10B25" type="main">
<s id="N10B27">E qvanto delli momenti paralleli habbiamo <lb/>moſtrato, tutto ſi adatterà anco alli momenti con­<lb/>correnti à centro: ſe in vece di linee dritte conſideria­<lb/>mo le circolari d'intorno il centro oue li momenti con­<lb/>corrono: &amp; in dette circolari ſi faccia l'iſteſſa partitione: <lb/>e ſe in vece delli corpi terminati, da ſuperficie parallele, <lb/>s'intendano altri corpi terminati, parte da ſuperficie sfe<lb/>riche c'habbiano detto centro: parte da ſuperficie pia<lb/>ne che paſſino per eſſo. </s></p><figure id="id.041.01.038.1.jpg" xlink:href="041/01/038/1.jpg"/>
<pb xlink:href="041/01/039.jpg" pagenum="38"/>
<p id="N10B3F" type="head">
<s id="N10B41">ROTE VET­<lb/>TIVE. </s></p><p id="N10B45" type="head">
<s id="N10B47"><emph type="italics"/>SVPPOSITIONE. <emph.end type="italics"/></s></p><p id="N10B4D" type="main">
<s id="N10B4F">Svpponiamo vna, o più rote congiogate, <lb/>muouerſi per piano, che ſia, o di poſitura orizontale, <lb/>o inchinata. </s></p><p id="N10B55" type="head">
<s id="N10B57"><emph type="italics"/>DEFINITION. <emph.end type="italics"/><lb/>I. </s></p><p id="N10B5F" type="main">
<s id="N10B61">Cogiogation ſemplice, diciamo delle rote, che ſono <lb/>sù di vn'iſteſſo aſſe. </s></p><p id="N10B65" type="head">
<s id="N10B67">I. </s></p><p id="N10B69" type="main">
<s id="N10B6B">Molteplice, delle rote che ſono in più aſſi. </s></p><p id="N10B6D" type="head">
<s id="N10B6F">III. </s></p><p id="N10B71" type="main">
<s id="N10B73">Portioni terminate dal ſoſtenimento diciamo nel cir<lb/>colo, le fatte dalla linea perpendicolare per lo ponto del <lb/>contatto, all'orizonte: e nel cilindro, dalla ſuperficie pia <lb/>na per la linea del contatto, perpendicolare ſimilmente <lb/>all'orizonte. </s></p>
<pb xlink:href="041/01/040.jpg" pagenum="39"/>
<p id="N10B80" type="head">
<s id="N10B82"><emph type="italics"/>POSITIONE. <emph.end type="italics"/><lb/>I. </s></p><p id="N10B8A" type="main">
<s id="N10B8C">Poniamo ogni forza, o trattiua, o pulſiua, giunger mo<lb/>mento uerſo quella parte, oue tira, o ſpinge. </s></p><p id="N10B90" type="head">
<s id="N10B92">II. </s></p><p id="N10B94" type="main">
<s id="N10B96">E ſe'l centro del peſo ſia nell'iſteſſa linea dell'appendi <lb/>mento, o ſoſtenimento: che la grauezza non habbia mo<lb/>mento, ne uerſo l'vna, ne uerſo l'altra parte. </s></p><figure id="id.041.01.040.1.jpg" xlink:href="041/01/040/1.jpg"/>
</chap>
<chap id="N10B9F">
<p id="N10BA0" type="head">
<s id="N10BA2"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>I. </s></p><p id="N10BAA" type="main">
<s id="N10BAC">Della rota vettiua, che ſi moue ſopra di vn piano ori­<lb/>zontale, il centro del peſo ſempre è nella perpendicola­<lb/>re del ſoſtenimento. </s></p><figure id="id.041.01.040.2.jpg" xlink:href="041/01/040/2.jpg"/>
<pb xlink:href="041/01/041.jpg" pagenum="40"/>
<p id="N10BB8" type="head">
<s id="N10BBA"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N10BC0" type="main">
<s id="N10BC2"><emph type="italics"/>Sia la linea Orizontale A B: il circolo che rappreſenta la rota, CD: <lb/>il ponto, oue detta rota tocca il piano C: da cui ſi cacci ad angoli ret­<lb/>ti la linea C D, è manifeſto che detta linea, è la perpendicolare del ſoſte<lb/>nimento: &amp; perquelche nelli libri Giometrici ſi moſtra: che paſſa per il <lb/>centro del circolo, che è il centro della rota e grauezza: perilche diui­<lb/>de il circolo il parti vguali, &amp; equeponderanti: è dunque il centro <lb/>del peſo nella perpendicolare del ſoſtenimento. </s>
<s id="N10BD2">Il che ſi hauea da <lb/>moſtrare,<emph.end type="italics"/></s></p><p id="N10BD8" type="head">
<s id="N10BDA"><emph type="italics"/>Appendice. </s>
<s id="N10BDE">I. <emph.end type="italics"/></s></p><p id="N10BE2" type="main">
<s id="N10BE4">Et il ſimile ſi moſtra, nelle ſemplici rote congiogate, <lb/>ſopra l'aſſe de quali, poſi la grauezza. </s></p><p id="N10BE8" type="head">
<s id="N10BEA"><emph type="italics"/>Appendice, II. <emph.end type="italics"/></s></p><p id="N10BF0" type="main">
<s id="N10BF2">Et è manifeſto nelle rote, sù l'aſſe de quali poſi la <lb/>grauezza: che nel piano <expan abbr="orizõ">orizon</expan>tale, non habbian momen­<lb/>to ne verſo l'vna, ne verſo l'altra parte. </s></p><p id="N10BFC" type="head">
<s id="N10BFE"><emph type="italics"/>Appendice. </s>
<s id="N10C02">III. <emph.end type="italics"/></s></p><p id="N10C06" type="main">
<s id="N10C08">E che perciò qual ſi voglia poſſanza, le porterà così <lb/>nell'vna, come nell'altra parte, </s></p>
<pb xlink:href="041/01/042.jpg" pagenum="41"/>
</chap>
<chap id="N10C0F">
<p id="N10C10" type="head">
<s id="N10C12"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>II. </s></p><p id="N10C1A" type="main">
<s id="N10C1C">Nella rota che ſi porta per piano inchinato, il centro <lb/>del peſo, è fuori della perpendicolare del ſoſtenimento. </s><lb/>
<s id="N10C21">et il momento della rota appoggiata al piano, al momen­<lb/>to della rota ſoſpeſa, la ha ragione, che l'ecceſſo delle <lb/>portioni del circolo, al circolo tutto. </s></p><figure id="id.041.01.042.1.jpg" xlink:href="041/01/042/1.jpg"/>
<pb xlink:href="041/01/043.jpg" pagenum="42"/>
<p id="N10C2D" type="head">
<s id="N10C2F"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N10C35" type="main">
<s id="N10C37"><emph type="italics"/>Sia la linea che rappreſenta il piano orizontale A B: la linea del pia <lb/>no inchinato A C: il circolo della rota D E FG: il toccamento D: e dal <lb/>ponto D, tiriſi perpendicolare all'orizonte B D F: è manifeſto che detta <lb/>linea, ſia la perpendicolare del ſoſtenimento: dico che'l centro del peſo <lb/>è fuori di detta linea. </s>
<s id="N10C43">Si moſtra: perche del triangolo D B A: l'angolo, <lb/>E, che fa la perpendicolare con l'orizonte, è retto: reſta l'angolo B D A, <lb/>a cuto: e perciò la portione D G F, e maggiore del ſemicircolo; &amp; in eſ<lb/>ſa ſarà il centro del circolo, che è anco centro di peſo. </s>
<s id="N10C4B">è dunque il cen­<lb/>tro del peſo fuori della linea del <expan abbr="ſoſtenimẽto">ſoſtenimento</expan>. </s>
<s id="N10C53">De ſcriuaſi alla D E, la por<lb/>tione di circolo D H F, ſimile a D E F; ſaranno dette portioni vgua­<lb/>li, e faranno equipondio. </s>
<s id="N10C59">reſta dunque la figura lunare ſenza equi<lb/>pondio: &amp; il momento della rota appoggiata ſarà meno che della ro<lb/>ta ſoſpeſa, ſecondo la ragione della figura lunare a tutto il circolo: cio è <lb/>ſecondo la ragione dell'ecceſſo delle portioni, al circolo tutto. </s>
<s id="N10C61">Il che <lb/>ſi hauea da moſtrare. <emph.end type="italics"/></s></p><p id="N10C67" type="head">
<s id="N10C69"><emph type="italics"/>Appendice. </s>
<s id="N10C6D">I. <emph.end type="italics"/></s></p><p id="N10C71" type="main">
<s id="N10C73">E l'iſteſſo che si è moſtrato nella rota c'ha grauezza; <lb/>si moſtra nelle rote al cui aſſe appoggi altro peſo. </s></p><p id="N10C77" type="main">
<s id="N10C79"><emph type="italics"/>Percio che ſe in vece del peſo appoggiato all'aſſe, intendiamo darſi <lb/>l'iſteſſo peſo alle rote: eſſendo peſi vguali con loro centri nell'iſteſſe li­<lb/>nee, &amp; la linea del ſoſtenimento l'iſteſſa, harranno li peſi l'iſteſſi <expan abbr="momẽti">momenti</expan>
<emph.end type="italics"/></s></p><p id="N10C86" type="head">
<s id="N10C88"><emph type="italics"/>Appendice, II. <emph.end type="italics"/></s></p><p id="N10C8E" type="main">
<s id="N10C90">Et è manifeſto che detta rota correrà verſo la parte <lb/>del piano inferiore. </s></p><p id="N10C94" type="main">
<s id="N10C96"><emph type="italics"/>Percioche tirata dal centro I, la IG K perpendicolare del momento <lb/>tutto ſin che <expan abbr="s'incõtri">s'incontri</expan> col piano per oue camina: ſarà il ponto G della cir<emph.end type="italics"/><pb xlink:href="041/01/044.jpg" pagenum="43"/><emph type="italics"/>conferenza diſcoſto dal <expan abbr="põto">ponto</expan> K del piano per oue camina la rota: e <expan abbr="tãto">tanto</expan> <lb/> <expan abbr="maggiormẽte">maggiormente</expan> il <expan abbr="põto">ponto</expan> oue <expan abbr="s'incõtra">s'incontra</expan> la <expan abbr="perpẽdicolare">perpendicolare</expan> del <expan abbr="cẽtro">centro</expan> di peſo del<lb/>la figura lunare: la cui <expan abbr="diſtãza">diſtanza</expan> dalla linea del <expan abbr="ſoſtenimẽto">ſoſtenimento</expan>, è maggior che <lb/>la diſtanza del centro del circolo, ſecondo la ragion di tutto il circolo al <lb/>la figura lunare. <emph.end type="italics"/></s></p>
</chap>
<chap id="N10CD4">
<p id="N10CD5" type="head">
<s id="N10CD7"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>III. </s></p><p id="N10CDF" type="main">
<s id="N10CE1">Se vn peſo ſia portato da due <expan abbr="cõgiogationi">congiogationi</expan> di rote, <lb/>ſarà il peſo ſoſtenuto dalli due aſſi compartitamente, ſe­<lb/>condo la ragione delle diſtanze del momento da gli aſſi, <lb/>reciprocamente. </s></p><figure id="id.041.01.044.1.jpg" xlink:href="041/01/044/1.jpg"/>
<p id="N10CF0" type="head">
<s id="N10CF2"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N10CF8" type="main">
<s id="N10CFA"><emph type="italics"/>Siano le due congiogationi di rote rappreſentate con li due circoli, <lb/>de quali gli <expan abbr="cẽtri">centri</expan> ſono A e B ponti, che rappreſentano li due aſſi: e dal <lb/>ponto A al B, tiriſi la A B. </s>
<s id="N10D06">&amp; intendaſi il centro del peſo tutto appo<lb/>giato a detti due aſſi hauere il momento nel ponto C della detta linea. <emph.end type="italics"/></s>
<pb xlink:href="041/01/045.jpg" pagenum="44"/>
<s><emph type="italics"/><emph type="italics"/>Dico che'l detto peſo è ſoſtenuto da detti aſſi compartitamente, ſecondo <lb/>la ragione delle BC, AC: cioè che di tutto il peſo l'aſſe A. </s>
<s id="N10D14">ne ſoſten­<lb/>terà tal portione qual'è BC di B A, e B tale qual'è AC di AB, Si mo<lb/>ſtra intendaſi <expan abbr="prolõgata">prolongata</expan> la AB nell'vna e l'altra banda, farſi ad AC <lb/>vguale la BD: &amp; alla BC, vguale la AE: ſaranno le EC, DC vguali: <lb/>e di nuouo fatto alla AC uguale la AE, ſaranno le DB, BF, e le AE <lb/>AF, vguali: e percio ſe alla linea DE, s'intenda fatta application di <lb/>corpo: il momento di tutto ſarà nel ponto C. </s>
<s id="N10D26">di cui il detto aſſe A ne <lb/>ſoſtentarà la portione applicata ad EF: e l'aſſe B la portione applicata <lb/>a DF, la ragion de quali è l'iſteſſa: che di BC ad AC: ma del corpo ap<lb/>plicato il centro del peſo è l'iſteſſo, dall'iſteſſi ponti ſoſtenuto. </s>
<s id="N10D2E">ſoſtengono <lb/>dunque gli aſſi il peſo compartitamente ſecondo la ragion di BC a C­<lb/>A. </s>
<s id="N10D34">Il che ſi hauea da mostrare. <emph.end type="italics"/></s></p>
</chap>
<chap id="N10D38">
<p id="N10D39" type="head">
<s id="N10D3B"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>IIII. </s></p><p id="N10D43" type="main">
<s id="N10D45">Se'l peſo sia portato da due <expan abbr="congiõgationi">congiongationi</expan> di rote per <lb/>piano inchinato: <expan abbr="ſoſtẽntarà">ſoſtenntarà</expan> l'aſſe delle rote inferiori di <lb/>detto peſo, maggior portione che ſe fuſſe nel piano ori<lb/>zontale. </s></p><p id="N10D55" type="head">
<s id="N10D57"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N10D5D" type="main">
<s id="N10D5F"><emph type="italics"/>Sia la linea del piano orizontale AB: del piano inchinato AC: li <lb/>centri de circoli delle rote D, &amp; E: il centro della grauezza che sù <lb/>gli aſſi di dette rote appoggia F: Dico che di detta grauezza, dall'aſſe <lb/>D, ne ſarà ſostentata maggior portione: e dall'aſſe E, minore, che ſe <lb/>portata fuſſe per piano Orizontale. </s>
<s id="N10D6B">Si moſtra: tiriſi da F perpendico<lb/>lare alla DE, che ſia FG: e perpendicolare all'orizonte che ſia FH: ſa <lb/>rà il ponto G, il ponto del momento nel ſito orizontale. </s>
<s id="N10D71">&amp; H, nell'in <lb/>chinato: e perche EH, è maggior portione di ED: che EG, e DH,<emph.end type="italics"/><pb xlink:href="041/01/046.jpg" pagenum="45"/><emph type="italics"/>minore che DG: ſoſtentarà la rota inferiore ſecondo la ragione di EH, <lb/>ad ED; e la ſuperiore <expan abbr="ſecõdo">ſecondo</expan> la ragione di DH ad ED: ſoſtenta <expan abbr="dũ">dun</expan>que <lb/>la rota inferiore, maggior portione di peſo: e la ſuperiore minor porti <lb/>one, che ſe nel ſito orizontale fuſſero. </s>
<s id="N10D8B">Il che ſi hauea da moſtrare. <emph.end type="italics"/></s></p><figure id="id.041.01.046.1.jpg" xlink:href="041/01/046/1.jpg"/>
</chap>
<chap id="N10D92">
<p id="N10D93" type="head">
<s id="N10D95"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>V. </s></p><p id="N10D9D" type="main">
<s id="N10D9F">Data la rota che <expan abbr="affõdi">affondi</expan> in <expan abbr="cõcauita">concauita</expan> ſotto il piano <expan abbr="orizõtale">orizon<pb xlink:href="041/01/047.jpg" pagenum="46"/>tale</expan>: e data qual si uoglia grauezza: ritrouare in vn rag<lb/>gio la diſtanza oltre di cui detta grauezza appeſa, ſol­<lb/>leui detta rota. </s></p><figure id="id.041.01.047.1.jpg" xlink:href="041/01/047/1.jpg"/>
<p id="N10DB8" type="head">
<s id="N10DBA"><emph type="italics"/>Dimostratione. <emph.end type="italics"/></s></p><p id="N10DC0" type="main">
<s id="N10DC2"><emph type="italics"/>Sia la linea del piano orizontale ABCD: la concauità in eſſa BE <lb/>C: la rota che affondi BCF: la grauezza data G. </s>
<s id="N10DC8">ſi cerca in vn raggio <lb/>della rota, ponto oltre di cui ſoſpeſa la G, ſolleui detta rota. </s>
<s id="N10DCC">Sia il cen­<lb/>tro H: la linea del raggio prodotto HFI: qual ſia parallela all'ori­<lb/>zonte: e dal <expan abbr="põto">ponto</expan> C, ſi tiri la CK perpendicolare che <expan abbr="affrõti">affronti</expan> la HF, in K: <lb/>e la ragion c'ha la grauezza G al peſo della rota, habbia HK a KI: è <lb/>manifeſto perche KC, è <expan abbr="perdendicolare">perpendicolare</expan> del ſoſtenimento, che dal ponto I <lb/>la grauezza G, fa equipondio alla rota. </s>
<s id="N10DE0">e che da ogni ponto oltre, la ſol <lb/>leui, il che ſi cerca un. <emph.end type="italics"/></s></p>
<pb xlink:href="041/01/048.jpg" pagenum="47"/>
<p id="N10DE9" type="head">
<s id="N10DEB">TAGLIA. </s><lb/>
<s id="N10DEE"><emph type="italics"/>SVPPOSITIONE. <emph.end type="italics"/></s></p><p id="N10DF4" type="main">
<s id="N10DF6">Svpponiamo la taglia c'habbia in ſe una, o più <lb/>girelle, o sia in vno o più ordini. </s>
<s id="N10DFA">Et delle taglie, ſta <lb/>bile diciamo, il cui collo sia legato ad vn termine: mo­<lb/>bile il cui collo sia legato al peſo. </s>
<s id="N10E00">Et <expan abbr="altrimẽte">altrimente</expan> mobile la <lb/>guidata da vna potenza, e che ad vn capo di eſſa ſia attac<lb/>cato il peſo. </s>
<s id="N10E0A">In oltre ſupponiamo della corda auuolta il <lb/>capo andare, o alla taglia, o ad'vn termine fiſſo, o a poſ­<lb/>ſanza, ò a peſo. </s></p><p id="N10E10" type="head">
<s id="N10E12"><emph type="italics"/>POSITIONE <emph.end type="italics"/><lb/>I. </s></p><p id="N10E1A" type="main">
<s id="N10E1C">Poniamo della girella a cui sia auuolta corda data <lb/>a pesi, &amp; a poſſanze, mentre detta girella non volta il mo<lb/>mento de capi eſſere vguale. </s></p><p id="N10E22" type="head">
<s id="N10E24">II. </s></p><p id="N10E26" type="main">
<s id="N10E28">Ma ſe la girella volta, il momento di quella corda eſ­<lb/>ſer maggiore, verſo di cui volta. </s></p><p id="N10E2C" type="head">
<s id="N10E2E">III. </s></p><p id="N10E30" type="main">
<s id="N10E32">E poniamo nelle girelle, di poſſanze e peſi vguali, <lb/>li momenti eſſere vguali. </s></p>
<pb xlink:href="041/01/049.jpg" pagenum="48"/>
</chap>
<chap id="N10E39">
<p id="N10E3A" type="head">
<s id="N10E3C"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>I. </s></p><p id="N10E44" type="main">
<s id="N10E46">Se delli due capi della girella, l'vna ſoſtenti peſo, l'al<lb/>tro ſia dato a poſſanza: la poſſanza del capo ſarà di mo<lb/>mento eguale al peſo. </s>
<s id="N10E4C">e la poſſanza della taglia ſoſtenta <lb/>rà il doppio. </s></p><p id="N10E50" type="head">
<s id="N10E52"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N10E58" type="main">
<s id="N10E5A"><emph type="italics"/>Sia la taglia AB: li capi della fune auuolta <emph.end type="italics"/><lb/><figure id="id.041.01.049.1.jpg" xlink:href="041/01/049/1.jpg"/><lb/><emph type="italics"/>A C, B D: dequali A C, ſoſtenti il peſo C: e B <lb/>D, ſia dato alla poſſanza in D: dico che la <lb/>poſſanza in D è di momento eguale al peſo: e <lb/>che la poſſanza in E, ſoſtenta il doppio. </s>
<s id="N10E6F">Si <lb/>moſtra: e prima che'l momento di D, ſia v­<lb/>guale al momento di C. </s>
<s>è manifeſto: perche <lb/>ſe l'vn di loro fuſſe maggiore, la girella volte<lb/>rebbe verſo detto momento: Jl che è contro <lb/>il ſuppoſto. </s>
<s id="N10E7B">Dico hora che la poſſanza della <lb/>taglia ſia doppia del peſo: percioche eſſendo <lb/>la poſſanza di D, equiualente al peſo C: ambi <lb/>C e D, ſono il doppio di eſſo C: ma la <expan abbr="poſsãza">poſsanza</expan> in <lb/>E, in quanto ſoſtiene, è vguale ad ambi: dun­<lb/>que è doppia di vn di loro. </s>
<s id="N10E8F">Haſſi dunque il <lb/>propoſto, che la poßanza D, ſia vguale al mo<lb/>mento di C: e che la E, ſoſtenti il doppio di eſſo. <emph.end type="italics"/></s></p>
<pb xlink:href="041/01/050.jpg" pagenum="49"/>
</chap>
<chap id="N10E9A">
<p id="N10E9B" type="head">
<s id="N10E9D"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>II. </s></p><p id="N10EA5" type="main">
<s id="N10EA7">Se li due capi di girella mobile, ſiano raccomanda­<lb/>ti a due poſſanze: ſoſtentarà così l'vna, come l'altra poſ<lb/>ſanza, la metà del peſo. </s></p><p id="N10EAD" type="head">
<s id="N10EAF"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N10EB5" type="main">
<s id="N10EB7"><emph type="italics"/>Sia la taglia A B, a cui ſia attaccato il pe<emph.end type="italics"/><lb/><figure id="id.041.01.050.1.jpg" xlink:href="041/01/050/1.jpg"/><lb/><emph type="italics"/>ſo C: li due capi della corda auuolta alla gi­<lb/>rella A D, B E: le poſſanze in D, et E: dico <lb/>che così l'vna, come l'altra poſſanza ſoſten<lb/>ta la metà del peſo. </s>
<s id="N10ECE">ſi moſtra: percioche ſtan­<lb/>do la girella <expan abbr="sẽza">senza</expan> voltare, <expan abbr="ſecõdo">ſecondo</expan> il ſup. ſara <lb/>di conſeguenza il momento dell'vn capo v­<lb/>guale al momento dell'altro: e perciò le poſ<lb/>ſanze anco eguali. </s>
<s id="N10EE0">e perche ambe ſoſtenta­<lb/>no il peſo C: e le poſſanze, in quanto ſoſten­<lb/>gono, ſono eguali alli peſi. </s>
<s id="N10EE6">ſono dunque am<lb/>be eguali al peſo C: e perciò diuiſamente l'v <lb/>na e l'altra ſarà la metà di detto peſo <lb/>al che ſi hauea da moſtrare. <emph.end type="italics"/></s></p>
<pb xlink:href="041/01/051.jpg" pagenum="50"/>
<p id="N10EF3" type="head">
<s id="N10EF5"><emph type="italics"/>Appendice,<emph.end type="italics"/></s></p><p id="N10EFB" type="main">
<s id="N10EFD">E perciò anco se l'vn capo sia raccomandato ad vn <lb/>termine fiſſo, l'altro a poſſanza: ſoſterrà la poſſanza la <lb/>metà del peſo. </s></p><p id="N10F03" type="main">
<s id="N10F05"><emph type="italics"/>Percioche mutato il termine in un'altra poſſanza: la poſſanza ſuppo<lb/>ſta ſoſterrà l'iſteſſa altra quantità di peſo che prima. <emph.end type="italics"/></s></p>
</chap>
<chap id="N10F0D">
<p id="N10F0E" type="head">
<s id="N10F10"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>III. </s></p><p id="N10F18" type="main">
<s id="N10F1A">Delle corde, che dalla taglia ſu<lb/>periore, &amp; dalla poſſanza alla ta<lb/><figure id="id.041.01.051.1.jpg" xlink:href="041/01/051/1.jpg"/><lb/>glia inferiore peruengono: ciaſcu<lb/>na ſoſtiene egual parte dipeſo. </s></p><p id="N10F27" type="head">
<s id="N10F29"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N10F2F" type="main">
<s id="N10F31"><emph type="italics"/>Sia la taglia ſuperiore A B: l'inferiore <lb/>C D: la corda auuolta no tata con l'iſteße let<lb/>tere: e di lei l'vn termine vada a ſoſtenere <lb/>la taglia inferiore in E: l'altro ſia dato al­<lb/>la poſſanza in F. </s>
<s id="N10F3D">Dico che ciaſcuna corda <lb/>ſoſtiene egual parte di peſo. </s>
<s id="N10F41">Si moſtra: <lb/>perche ſtando la girella A B, il momento <lb/>del capo B D è eguale al momento del ca­<lb/>po A E: e del capo C F, al capo B D, per <lb/>la girella C D: ſono <expan abbr="dũque">dunque</expan> tutte di momen­<lb/>to eguali: perciò ciaſcuna ſoſtentarà e­<lb/>gual parte di peſo. </s>
<s id="N10F53">e ſe il capo A E non fuſ<lb/>ſe ligato alla taglia, ma ad altro termine, ſa<lb/>rebbe l'iſteſſo, ma il numero delle corde di <lb/>vna meno. </s>
<s id="N10F5B">Il che ſi hauea da moſtrare. <emph.end type="italics"/></s></p>
<pb xlink:href="041/01/052.jpg" pagenum="51"/>
</chap>
<chap id="N10F62">
<p id="N10F63" type="head">
<s id="N10F65"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>IIII. </s></p><p id="N10F6D" type="main">
<s id="N10F6F">Se l'vn capo della fune auuolta <lb/><figure id="id.041.01.052.1.jpg" xlink:href="041/01/052/1.jpg"/><lb/>a girelle, ſia raccomandato alla ta<lb/>glia ſuperiore: il peſo ſoſtenuto <lb/>è diſtribuito in parti di numero <lb/>pare. </s></p><p id="N10F7E" type="head">
<s id="N10F80"><emph type="italics"/>Dimostratione. <emph.end type="italics"/></s></p><p id="N10F86" type="main">
<s id="N10F88"><emph type="italics"/>Sia la taglia inferiore e mobile AC B D: <lb/>la ſuperiore E F G H: la fune auuolta nota<lb/>ta <expan abbr="cõ">con</expan> l'isteſſe lettere: il termine del capo C 1, <lb/>attaccato alla taglia ſuperiore, <expan abbr="s'intẽda">s'intenda</expan> eſſe <lb/>re in I: l'altro termine raccomandato alla <lb/>poſſanza s'intenda eſſere o in K del capo B <lb/>K, che vien dalla taglia inferiore, o in L, del <lb/>capo G L, che vien dalla taglia ſuperiore. </s><lb/>
<s id="N10FA4">Dico che, e nell'vno, e nell'altro modo, il pe<lb/>ſo è diſtribuito in parti di numero pare. </s><lb/>
<s id="N10FA9">Si moſtra: percioche venendo alla girella <lb/>C D due corde, l'vna da taglia, l'altra da <lb/>girella E F: ſaranno detti capi di momen­<lb/>ti eguali: perche ſi pone la girella non vol <lb/>tare. </s>
<s id="N10FB3">ſimilmente perche alla girella A B <lb/>vengono due corde, l'vna dalla girella EF, <lb/>che è la corda E A, l'altra dalla poßanza <lb/>K, che è la corda KB: ſaranno dette corde <lb/>di <expan abbr="momẽti">momenti</expan> eguali. </s>
<s id="N10FC1">ma la DF, è di momento <lb/>eguale alla A E, e alla B K: ſono dunque <lb/>tutte tra di loro di momento eguale: e <lb/>ſono di numero pare: percioche a cia­<emph.end type="italics"/><pb xlink:href="041/01/053.jpg" pagenum="52"/><emph type="italics"/>ſcuna girella ne vengono due. </s>
<s id="N10FD1">perche dunque il peſo è ſoſtenuto da <lb/>dette corde di <expan abbr="momẽto">momento</expan> eguale: perciò, mentre l'vn capo ſia attaccato <lb/>alla taglia ſuperiore, l'altro dato alla poſſanza, il <expan abbr="momẽto">momento</expan> del peſo è di<lb/>ſtribuito in parti di numero pare: ne altro auuiene, ſe la poßanza ſia in <lb/>L, nel capo, che viene dalla taglia ſuperiore: percioche il numero del<lb/>le corde, che alla taglia inferiore peruengono è l'iſteſſo. <emph.end type="italics"/></s></p><p id="N10FE7" type="head">
<s id="N10FE9"><emph type="italics"/>Appendice. </s>
<s id="N10FED">I<emph.end type="italics"/></s></p><p id="N10FF1" type="main">
<s id="N10FF3">Et è manifeſto, che poſta vna girella meno nella ta­<lb/>glia ſuperiore, ſi ſoſterrà dalla poſſanza l'iſteſſo che ſe <lb/>fuſſero le girelle ſuperiori di numero eguale alle in­<lb/>feriori, è che per detta girella aggiunta, si muta ſo<lb/>lamente l'un momento nell'altro di ſpezie contraria. </s></p>
</chap>
<chap id="N10FFD">
<p id="N10FFE" type="head">
<s id="N11000"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>V. </s></p><p id="N11008" type="main">
<s id="N1100A">Se l'vn capo della fune auuolta a girelle, ſia racco­<lb/>mandato alla taglia inferiore: il peſo ſoſtenuto è diſtri<lb/>buito in parti di numero ſpare. </s></p><p id="N11010" type="head">
<s id="N11012"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N11018" type="main">
<s id="N1101A"><emph type="italics"/>Sia la taglia ſuperiore e stabile AB, CD: l'inferiore e mobile E­<lb/>F, G H: la fune auuolta notata con l'iſteſſe lettere: e di eſſa l'vn ter­<lb/>mine I, che è del capo C I, ſia attaccato alla taglia inferiore: et il termi<lb/>ne K, del capo E K, raccomandato alla poſſanza in K: dico che'l peſo è<emph.end type="italics"/><pb xlink:href="041/01/054.jpg" pagenum="53"/><emph type="italics"/>diſtribuito in parti dinumero ſpare. </s>
<s id="N1102C">Si <emph.end type="italics"/><lb/><figure id="id.041.01.054.1.jpg" xlink:href="041/01/054/1.jpg"/><lb/><emph type="italics"/>moſtra: percioche vengono due capi dalla <lb/>girella C D, alla taglia inferiore, e due <lb/>dalla A B, e ſimilmente da qual ſi voglia <lb/>altra girella: ſono dunque li capi, che dal <lb/>le girelle alla taglia vengono, di numero <lb/>pare. </s>
<s id="N11043">et euui in oltre il capo della poſſan<lb/>za: ſono dunque tutti di numero ſpare. </s><lb/>
<s id="N11048">e ſono, per quel che ſi è detto nelle prece <lb/>denti, tutte di momento eguale: dunque <lb/>il peſo è diſtribuito in parti di numero <lb/>ſpare. </s>
<s id="N11050">Jl che ſi hauea da moſtrare. <emph.end type="italics"/></s></p><p id="N11054" type="head">
<s id="N11056"><emph type="italics"/>Appendice. </s>
<s id="N1105A">I. <emph.end type="italics"/></s></p><p id="N1105E" type="main">
<s id="N11060">Et è manifeſto, che aggionta <lb/>alla taglia ſuperiore vna girel­<lb/>la, si commuta ſolamente il mo­<lb/>mento della poſſanza, in mo­<lb/>mento di ſpezie contraria. </s></p><p id="N1106A" type="head">
<s id="N1106C"><emph type="italics"/>Appendice. </s>
<s id="N11070">II. <emph.end type="italics"/></s></p><p id="N11074" type="main">
<s id="N11076">E raccogliamo, che ligato l'vn <lb/>capo alla taglia ſuperiore, puote <lb/>ſtar detta taglia con vna girella <lb/>meno: e ligata all'inferiore con <lb/>vna girella più. </s></p>
<pb xlink:href="041/01/055.jpg" pagenum="54"/>
</chap>
<chap id="N11083">
<p id="N11084" type="head">
<s id="N11086"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>VI</s></p><p id="N1108E" type="main">
<s id="N11090">Se vn capo della taglia ſupe<lb/><figure id="id.041.01.055.1.jpg" xlink:href="041/01/055/1.jpg"/><lb/>riore sia raccomandato ad vn <lb/>termine fiſſo: ſarà il peſo diſtri<lb/>buito in parti di numero pare. </s></p><p id="N1109D" type="head">
<s id="N1109F"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N110A5" type="main">
<s id="N110A7"><emph type="italics"/>Sia la taglia ſuperiore A B C D, l'­<lb/>inferiore E F G H: la fune auuolta a gi<lb/>relle notata con l'iſteſſe lettere: di cui <lb/>il capo D I dalla girella C D della taglia <lb/>ſuperiore ſia raccomandato ad I termi<lb/>ne fiſſo: &amp; il capo F K, dalla girella E F, <lb/>della taglia inferiore, raccomandato al <lb/>la poſſanza in K. </s>
<s id="N110B9">Dico che'l peſo è diſtri<lb/>buito in parti di numero pare. </s>
<s id="N110BD">Si mo­<lb/>ſtra: percio che venendo alla taglia infe<lb/>riore le corde ſolo delle girelle, &amp; da cia<lb/>ſcuna girella due corde, quali tutte ſi è <lb/>moſtrato che ſoſtentino egual momento: <lb/>ſarà il peſo diſtribuito in corde di nume<lb/>ro pare, che egualmente ſoſtentano: e <lb/>perciò ſarà diſtribuito in dette parti. </s>
<s id="N110CD">Il <lb/>che ſi hauea da moſtrare. <emph.end type="italics"/></s></p><p id="N110D3" type="head">
<s id="N110D5"><emph type="italics"/>Correlario. </s>
<s id="N110D9">I. <emph.end type="italics"/></s></p><p id="N110DD" type="main">
<s id="N110DF">E manifeſto dunque che li<lb/>gato il capo di ſopra alla taglia <pb xlink:href="041/01/056.jpg" pagenum="55"/>inferiore, il peſo è diſtribuito in parti di numero ſpare, <lb/>et comunque altrimente, in parti di numero pare. </s></p><p id="N110E9" type="head">
<s id="N110EB"><emph type="italics"/>Correlario. </s>
<s id="N110EF">II. <emph.end type="italics"/></s></p><p id="N110F3" type="main">
<s id="N110F5">Et attaccato il capo di girella inferiore alla taglia ſu<lb/>periore, o à qual si voglia termine fiſſo: che la taglia in<lb/>feriore habbia vna girella più. </s></p>
</chap>
<chap id="N110FB">
<p id="N110FC" type="head">
<s id="N110FE"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>VII. </s></p><figure id="id.041.01.056.1.jpg" xlink:href="041/01/056/1.jpg"/>
<p id="N11109" type="main">
<s id="N1110B">Se'l peſo sia moſſo con ta<lb/>glie, quanto il peſo è moltepli<lb/>ce della poſſanza ſoſtenente, <lb/>tanto lo ſpatio, che detta <expan abbr="poſ­sãza">poſ­<lb/>sanza</expan> camina, è molteplice del<lb/>lo ſpatio caminato dal peſo. </s></p><p id="N1111B" type="head">
<s id="N1111D"><emph type="italics"/>Dimostratione. <emph.end type="italics"/></s></p><p id="N11123" type="main">
<s id="N11125"><emph type="italics"/>Sia la girella della taglia ſuperiore <lb/>A B: della inferiore nella prima po­<lb/>ſitione ſia C D: e la poſſanza che ſoſtie<lb/>ne il capo ſia in E: della ſeconda poſi <lb/>tione ſia in G H, e la poſſanza in I. </s>
<s id="N11131">Di <lb/>co che lo ſpatio caminato dalla taglia <lb/>mobile e peſo, è tal parte dello ſpatio <lb/>E I, qual la poſſanza ſoſtenente in E <lb/>è parte del peſo. </s>
<s id="N1113B">Si moſtra: perche <lb/>quante ſono la corde, che alla taglia <emph.end type="italics"/><pb xlink:href="041/01/057.jpg" pagenum="56"/><emph type="italics"/>inferiore peruengono, ſecondo tal numero la poſſanza che ſoſtiene è <lb/>parte del peſo: e perche nel mouimento della taglia ciaſcuna corda <lb/>ſi abbreuia egualmente, portata C D, in H G: le C G, D H parti del<lb/>la corda auuolta, quante ſi ſiano, pigliate inſieme, ſarano di lunghezza <lb/>tanto molteplici dello ſpatio caminato, quanto è il numero delle cor<lb/>de. </s>
<s id="N11151">ma la corda E A B D C F, è vguale alla I A B H G: dunque tol<lb/>tone di commune la F G H B A E, reſta le E I, eguale alla G C D H: <lb/>e percio E I, ſarà altre tanto molteplice dello ſpatio caminato, quan<lb/>to erano le corde C G, D H. </s>
<s id="N11159">ciò è il peſo tutto del peſo da vna corda <lb/>ſostenuto. </s>
<s id="N1115D">Il che ſi hauea da moſtrare. <emph.end type="italics"/></s></p>
</chap>
<chap id="N11161">
<p id="N11162" type="head">
<s id="N11164"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>VIII. </s></p><p id="N1116C" type="main">
<s id="N1116E"><emph type="italics"/>Problema. </s>
<s id="N11172">I. <emph.end type="italics"/></s></p><p id="N11176" type="main">
<s id="N11178">Data qual si voglia grauezza, e poſſanza: ritroua <lb/>re il minor numero di girelle nella taglia, con quali <lb/>la data poſſanza moua il dato peſo. </s></p><p id="N1117E" type="head">
<s id="N11180"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N11186" type="main">
<s id="N11188"><emph type="italics"/>Sia la data grauezza A, la poſſanza B: a cui ſi pigli vn peſo e­<lb/>quiualente C: e moltiplichiſi C, ſin che la prima volta ecceda la <lb/>grauezza A, il che ſia per il numero D. </s>
<s id="N11190">ſe dunque D è pare piglin <lb/>ſi nella taglia inferiore altre tante girelle, quante vnità ſono nella <lb/>inetà del numero: è manifeſto che la poſſanza mouerà il peſo con le <lb/>date girelle: ma ſe D ſia ſpare, toltane vnità, piglinſi girelle quan<lb/>te vnità ſono nella metà del reſto, e ligheſi vn delli capi alla taglia: <lb/>è manifesto ſimilmente che mouerà la poſſanza la data grauezza. </s><lb/>
<s id="N1119D">Il che ſi cercaua. <emph.end type="italics"/></s></p>
<pb xlink:href="041/01/058.jpg" pagenum="57"/>
</chap>
<chap id="N111A4">
<p id="N111A5" type="head">
<s id="N111A7"><emph type="italics"/>PROPOSITIONE. <emph.end type="italics"/><lb/>VIII. </s></p><p id="N111AF" type="main">
<s id="N111B1"><emph type="italics"/>Problema. </s>
<s id="N111B5">II. <emph.end type="italics"/></s></p><p id="N111B9" type="main">
<s id="N111BB">Data qual ſi voglia velocità, e data la tardità della <lb/>poſsanza: applicar o vna taglia di più girelle, o più ta<lb/>glie di vna girella, ſi che la poſſanza moua il dato pe­<lb/>ſo in velocità magior della data. </s></p><p id="N111C3" type="head">
<s id="N111C5"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N111CB" type="main">
<s id="N111CD"><emph type="italics"/>Pigliſi lo ſpatio che nel dato tem­<emph.end type="italics"/><lb/><figure id="id.041.01.058.1.jpg" xlink:href="041/01/058/1.jpg"/><lb/><emph type="italics"/>po camini la poſſanza: e lo ſpatio che <lb/>vogliamo che la coſa camini, e ſi mol<lb/>tiplichi il minore fin che la prima vol<lb/>ta auanzi, e quanto queſto è molte­<lb/>plice, tante corde ſiano nella taglia ſu<lb/>periore, pigliando la metà di girelle ſe <lb/>ſia pare, &amp; ſe ſia ſpare, ligando vn ca<lb/>po ad eſſa taglia ſuperiore. </s>
<s id="N111EA">Ligato dun<lb/>que il peſo ad vn capo, la poſſanza, che <lb/>tira la taglia, tirerà anco il peſo: e ca­<lb/>minerà lo ſpatio moltiplice al moui­<lb/>mento di eſſa poſſanza. </s>
<s id="N111F4">Ma, ſe vo<lb/>gliamo far ciò con piú taglie di vna gi<lb/>rella, radoppiſi lo ſpatio, e di nuouo il <lb/>fatto dal radoppiamento ſi radoppij: e <lb/>ciò ſi torni a fare, si che l'ultimo radop<lb/>piamento auanzi lo ſpatio maggiore. </s><lb/>
<s id="N11201">Se dunque, quante volte ſi è radoppia­<lb/>to, tanto numero ditaglie ſi pigli, si mo<lb/>uer à il peſo ſecondo la ragion del radop<lb/>piamento dello ſpatio, e perciò ſi mo­<lb/>uerà con maggior velocità della data. <emph.end type="italics"/></s></p>
<pb xlink:href="041/01/059.jpg" pagenum="58"/>
<p id="N11210" type="head">
<s id="N11212">ROTE MO<lb/>TIVE. </s></p><figure id="id.041.01.059.1.jpg" xlink:href="041/01/059/1.jpg"/>
<p id="N11219" type="head">
<s id="N1121B"><emph type="italics"/>SVPPOSITION. <emph.end type="italics"/><lb/>I. </s></p><p id="N11223" type="main">
<s id="N11225">Svpponiamo il mouimento di rote in aſſi <lb/>che ſtanno co'l toccamento, communicarſi l'vna <lb/>all'altra il mouimento: e che'l momento della poſſan­<lb/>za ſia per linea che faccia angolo retto co'l raggio di <lb/>eſſa rota: e de momenti altri eſſer concorrenti, altri <lb/>contrarij. </s></p><p id="N11231" type="head">
<s id="N11233"><emph type="italics"/>DEFINITION. <emph.end type="italics"/><lb/>I. </s></p><p id="N1123B" type="main">
<s id="N1123D">Concorrenti momenti diciamo quelli, che portan­<lb/>do verſo l'iſteſſa parte, ſi accreſcono. </s></p><p id="N11241" type="head">
<s id="N11243">II. </s></p><p id="N11245" type="main">
<s id="N11247">Contrarij quelli, che s'impediſcono portando in <lb/>contrario. </s></p><p id="N1124B" type="head">
<s id="N1124D"><emph type="italics"/>POSITION. <emph.end type="italics"/><lb/>I. </s></p><p id="N11255" type="main">
<s id="N11257">Poniamo, poſſanze eguali in circonferenze direte <lb/>eguali, hauer momenti eguali. </s></p>
<pb xlink:href="041/01/060.jpg" pagenum="59"/>
<p id="N1125E" type="head">
<s id="N11260"><emph type="italics"/>POSITION. <emph.end type="italics"/><lb/>II. </s></p><p id="N11268" type="main">
<s id="N1126A">Et in rote ineguali hauer momento ineguale, ſecon<lb/>do la ragion de ſemidiametri. </s></p><p id="N1126E" type="head">
<s id="N11270">III. </s></p><p id="N11272" type="main">
<s id="N11274">E gli momenti contrarij, per quanto ſi annullano, l' <lb/>vno eſſere eguale all'altro. </s></p><p id="N11278" type="head">
<s id="N1127A"><emph type="italics"/>PROPOSITION. <emph.end type="italics"/><lb/>I. </s></p><p id="N11282" type="main">
<s id="N11284">Se quante ſi voglia rote, vna per aſſe, ſi tocchino: <lb/>e poſte le poſſanze l'vna nella circonferenza della pri<lb/>ma, e l'altra dell'vltima, ſi rattengano: ſaranno le poſ<lb/>ſanze eguali. </s></p><figure id="id.041.01.060.1.jpg" xlink:href="041/01/060/1.jpg"/>
<pb xlink:href="041/01/061.jpg" pagenum="60"/>
<p id="N11292" type="head">
<s id="N11294"><emph type="italics"/>Dimostratione. <emph.end type="italics"/></s></p><p id="N1129A" type="main">
<s id="N1129C"><emph type="italics"/>Siano quante ſi voglia rote ne gli aſſi A, B, C, che ſi tocchino: ciò <lb/>è che la A tocchi la B nel ponto D: e la B tocchila C nel ponto E: <lb/>&amp; intendaſi nella circonferenza di A eſſer la potenza F: e nella cir<lb/>conferenza di C la potenza G: che l'una rattenga l'altra. </s>
<s id="N112A6">Dico che <lb/>le potenze ſono eguali. </s>
<s id="N112AA">Si moſtra: percio che la poßanza in F, è dell'­<lb/>iſteſſo momento, che ſe fuſſe in D, dell'iſteſſa rota A: ma il ponto <lb/>D, è ponto commune a due rote: e la poſſanza in D della rota B, <lb/>è quanto fuſſe in E: ſarà dunque la poſſanza in F l'iſteſſo che ſi fuſſe <lb/>in E: perche <expan abbr="dũque">dunque</expan> la poſſanza in F ſi annulla con la poſſanza in G, ſo<lb/>no li loro momenti eguali. </s>
<s id="N112BA">Ma le poſſanze che ſono in un'iſteſſa rota <lb/>di momenti eguali, ſono eguali: dunque la poſſanza in F è uguale alla <lb/>poſſanza in G. </s>
<s id="N112C0">Jl che ſi hauea da moſtrare. <emph.end type="italics"/></s></p><p id="N112C4" type="head">
<s id="N112C6"><emph type="italics"/>PROPOSITION. <emph.end type="italics"/><lb/>II. </s></p><p id="N112CE" type="main">
<s id="N112D0">Delle due rote in vno aſſe la poſſanza, che fa egual <lb/>momento nella rota magiore è di valor minore: e nel <lb/>la minore è di valor maggiore, nella ragione de ſemi <lb/>diametri reciproca. </s></p><p id="N112D8" type="head">
<s id="N112DA"><emph type="italics"/>Dimostratione. <emph.end type="italics"/></s></p><p id="N112E0" type="main">
<s id="N112E2"><emph type="italics"/>Siano ſu l' aſſe A le rote A B, A C: &amp; intendaſi la poſſanza B, <lb/>in circonferenza della rota maggiore, hauere egual momento alla <lb/>poſſanza C in circonferenza della rota minore. </s>
<s id="N112EA">Dico che la poſſan­<lb/>za B è minore della poſſanza C, ſecondo la ragione di C A ad A B. </s><lb/>
<s id="N112EF">Si moſtra: intendaſi nell circonferenza di A C eſſer poſſanza eguale <lb/>a B, che ſia D: ſarà il momento di B al momento di D, nella ragion <emph.end type="italics"/><pb xlink:href="041/01/062.jpg" pagenum="61"/><figure id="id.041.01.062.1.jpg" xlink:href="041/01/062/1.jpg"/><lb/><emph type="italics"/>della linea dritta B A alla D A: ma il momento di B, è uguale al <lb/>momento di C: dunque il momento di C al momento di D, è come <lb/>B A ad A D. </s>
<s id="N11304">Se dimque le poſſanze dell'iſteſſa rota ſono tra di loro <lb/>nella ragione delli momenti: ſarà di conſeguenza la poſſanza in D <lb/>alla poſſanza in C, come il ſemidiametro D A, al ſemidiame­<lb/>tro A B, e del diametro tutto a tutto. </s>
<s id="N1130C">Il che ſi hauea da mo­<lb/>ſtrare. <emph.end type="italics"/></s></p>
<pb xlink:href="041/01/063.jpg" pagenum="62"/>
<p id="N11315" type="head">
<s id="N11317"><emph type="italics"/>PROPOSITION. <emph.end type="italics"/><lb/>III. </s></p><p id="N1131F" type="main">
<s id="N11321">Se le rote, poſte a due in ciaſcun aſſe, ſi tocchino: <lb/>e le poſſanze, poſte l'vna nella prima, l'altra nell'vl­<lb/>tima rota, ſi rattengano: ſarà la ragion dell'vna poſſan<lb/>za all'altra l'iſteſſa, che la ragion compoſta delli ſemi <lb/>diametri, che ſono ſu l'iſteſſo aſſe, pigliate reciproca­<lb/>mente. </s></p><p id="N1132D" type="head">
<s id="N1132F"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N11335" type="main">
<s id="N11337"><emph type="italics"/>Siano ſu l'aſſe A, le due rote A B, A C: e ſu l'aſſe D, le rote D C <lb/>D F: &amp; intendaſi la rota D C, eſſer toccata dalla A C nel ponto C: <lb/>c l'una poſſanza eſſere in B l'altra in E. </s>
<s id="N1133F">Dico che la poſſanza in B,<emph.end type="italics"/><lb/><figure id="id.041.01.063.1.jpg" xlink:href="041/01/063/1.jpg"/><lb/><emph type="italics"/>alla poſſanza in F ha la ragion compoſta delle ragioni di F D a D C,<emph.end type="italics"/><pb xlink:href="041/01/064.jpg" pagenum="63"/><emph type="italics"/>e di C A ad A B, che ſono le ragioni de ſemidiametri reciprocamen<lb/>te pigliati. </s>
<s id="N11356">Si moſtra: percioche eſſendo il momento in B uguale al <lb/>momento in C, perche ſono in vno iſteſſo aſſe: &amp; il momento in C al <lb/>momento in F, per l'isteſſa ragione: &amp; è la poſſanza in F, alla <lb/>poſſanza in C, come il diametro C D a D F: e la poſſanza in C, <lb/>alla poſſanza in B, co me B A ad A C. </s>
<s id="N11360">Dunque la poſſanza in F alla <lb/>poſſanza in B, ha la ragion compoſta di C D a D F c di B A ad A C, <lb/>che è la ragion compoſta delle ragioni de diametri reciprocamente <lb/>pigliati. </s>
<s id="N11368">Jl che ſi hauea da moſtrare. <emph.end type="italics"/></s></p><p id="N1136C" type="head">
<s id="N1136E"><emph type="italics"/>DEFINITIONE. <emph.end type="italics"/></s></p><p id="N11374" type="main">
<s id="N11376">Momento della rota diciamo, il momento del pon<lb/>to poſto nella circonferenza di eſſa rota. </s></p><p id="N1137A" type="head">
<s id="N1137C"><emph type="italics"/>PROPOSITION. <emph.end type="italics"/><lb/>IIII. </s></p><p id="N11384" type="main">
<s id="N11386">Se in vna congiogation di rote ineguali, o in più, <lb/>che la minor dell'vna congiogatione tocchi la mag­<lb/>gior dell'altra, ſi ponga la poſſanza in vna di dette <lb/>rote: ſarà il momento dell'vltima minor rota, maggior <lb/>del momento della prima maggior rota, ſecondo la ra­<lb/>gion compoſta delli diametri. </s>
<s id="N11392">e la velocità ſarà mino<lb/>re, ſecondo l'iſteſſa ragion de diametri. </s></p><p id="N11396" type="head">
<s id="N11398"><emph type="italics"/>Dimoſtratione. <emph.end type="italics"/></s></p><p id="N1139E" type="main">
<s id="N113A0"><emph type="italics"/>Siano le congiogationi di rote, de quali gli aſsi ſiano A e B: &amp; in­<lb/>tendaſi ſu l'aſſe A eſſer la rota maggiore A C, e la minore A D,<emph.end type="italics"/><pb xlink:href="041/01/065.jpg" pagenum="64"/><figure id="id.041.01.065.1.jpg" xlink:href="041/01/065/1.jpg"/><lb/><emph type="italics"/>e ſu l' aſſe B, eſſer la maggiore D B, e la minore B E: e ſia il contat<lb/>to della minore di vn'ordine, con la maggiore dell'altro, il ponto D: <lb/>e ſuppongaſi prima la poſſanza porſi nella circonferenza di A C. </s><lb/>
<s id="N113B8">Dico che'l momento della rota A D, è maggiore del momento di <lb/>A C, secondo la ragione della linea C A ad A D. </s>
<s id="N113BC">Si moſtra: per<lb/>cioche poſta in D una poſſanza di <expan abbr="momẽto">momento</expan> eguale alla poſſanza in C, <lb/>ſarà detta poſſanza in D, maggiore, che la poſſanza in C: ma il mo<lb/>mento della rota, oue è poſta la poſſanza, è uguale ad eſſa poſſan­<lb/>za: ſarà dunque il <expan abbr="momẽto">momento</expan> della rota A D maggiore che della rota <lb/>A C ſecondo la ragion de diametri: queſto in una congiogatione <lb/>&amp; in più: per che il momento della circonferenza di A D è l'iſteſſo <lb/>che della circonferenza di B D, per lo contatto, che fa communi­<lb/>canza: ma il momento della circonferenza di B E, è di forza <lb/>maggiore che di B D <expan abbr="ſecõdo">ſecondo</expan> la ragione del diametro, B D a B E: <lb/>dunque fatta compoſitione de ragioni il momento della circonferen<lb/>za di B E, è maggiore del momento della circonferenza di C A ſe <lb/>condo la ragion compoſta di B D a B E, e di C A ad A D. </s>
<s id="N113E2">Il che <lb/>ſi hauea da moſtrare. <emph.end type="italics"/></s></p><p id="N113E8" type="main">
<s id="N113EA"><emph type="italics"/>Dico che la uelocità è minore nella iſteſſa ragione: il che è mani­<emph.end type="italics"/><pb xlink:href="041/01/066.jpg" pagenum="65"/><emph type="italics"/>feſto: percioche la velocità delle rote, che nell'iſteſſo tempo finiſcono <lb/>il circuito, è proportionale alle circonferenze di eſſe rote: e le circon<lb/>ferenze ſono di quantità proportionale alli diametri. </s>
<s id="N113FA">Sono dunque le <lb/>velocità delle rote proportionali alli diametri. </s>
<s id="N113FE">Jl che ſi hauea da <lb/>moſtrare. <emph.end type="italics"/></s></p><p id="N11404" type="head">
<s id="N11406"><emph type="italics"/>PROPOSITION. <emph.end type="italics"/><lb/>V. </s></p><p id="N1140E" type="main">
<s id="N11410">Date due poſſanze di momento contrario, l'vna mi<lb/>nore, e l'altra maggiore: e data la ragione dell'vna al­<lb/>l'altra delle due rote congiogate: ritrouar il minor nu­<lb/>mero de congiogationi, ſiche la data poſſanza minore <lb/>vinca la maggiore. </s></p><figure id="id.041.01.066.1.jpg" xlink:href="041/01/066/1.jpg"/>
<pb xlink:href="041/01/067.jpg" pagenum="96"/>
<p id="N11420" type="head">
<s id="N11422"><emph type="italics"/>Dimostratione. <emph.end type="italics"/></s></p><p id="N11428" type="main">
<s id="N1142A"><emph type="italics"/>Siano le date poſſanze di momento contrario A, B: De quali A <lb/>ſia la maggiore, c B la minore.: la ragion delle rote congiogate ſia di <lb/>C a D: ſi cerca il minor numero de congiogationi, ſiche la poſſanza <lb/>B minore vinca la A maggiore. </s>
<s id="N11434">Piglinſi nella ragione di C a D con<lb/>tinuamente le C, D, E, F: ſiche la C ad F habbia maggior ragione <lb/>che l' A a B: &amp; eguale di numero all'interualli de termini ſi piglino <lb/>le congiogationi di rote G, H, I: e ſiano ſu l'aſſe G, le rote G K, G <lb/>L, ſu l'aſſe H le rote H L, H M: e ſu l'aſſe I le rote M I, I N. </s>
<s id="N1143E">E ma<lb/>nifeſto che'l momento della <expan abbr="poſsãza">poſsanza</expan> in K, al momento ſuo in N, ha la <lb/>ragion compoſta delle ragioni de ſemidiametri: e perciò poſta la poſ­<lb/>ſanza maggiore A in N: e la minore B in K: ſara il momento della B <lb/>in K, maggiore che'l momento dell' A in N. </s>
<s id="N1144C">Il che ſi hauea da <lb/>trouare. <emph.end type="italics"/></s></p><p id="N11452" type="head">
<s id="N11454"><emph type="italics"/>PROPOSITION. <emph.end type="italics"/><lb/>VI. </s></p><p id="N1145C" type="main">
<s id="N1145E">Data qualſivoglia tardità di poſſanza, &amp; qualſivo<lb/>glia velocità: e data la ragion de diametri delle rote <expan abbr="cõgiogate">con<lb/>giogate</expan>: ritrouar vn minimo numero de congiogatio <lb/>ni, ſi che la data poſſanza moua la coſa con velocità <lb/>maggiore della data. </s></p><p id="N1146C" type="head">
<s id="N1146E"><emph type="italics"/>Dimostratione. <emph.end type="italics"/></s></p><p id="N11474" type="main">
<s id="N11476"><emph type="italics"/>Sia la poſſanza tarda A, la veloce B, lo ſpatio caminato da A in <lb/>vn dato tempo ſia C, lo C caminato da B nell'iſteſſo tempo ſia D: la <lb/>ragion de diametri congiogati ſia di E, ad F: biſogna ritrouare il <emph.end type="italics"/><pb xlink:href="041/01/068.jpg" pagenum="67"/><figure id="id.041.01.068.1.jpg" xlink:href="041/01/068/1.jpg"/><lb/><emph type="italics"/>minimo numero de <expan abbr="cõgiogationi">congiogationi</expan>, col quale la tarda A moua con ve<lb/>locità maggior che'l B. </s>
<s id="N11491">Piglinſi le E, F, G, continuate nella ragion <lb/>de diametri, che la prima volta l'interuallo della prima all'vltima <lb/>dico di G ad E, ſia maggiore che di C a D: e quanti interualli ſono il <lb/>E, F, G: tante congiogationi di rote ſi piglino nella iſteſſa ragione: l'a<lb/>ſe de quali ſiano H, I: e nello aſſe H, la minor rota ſia H K, la maggio <lb/>re H L: e nell'aſſe I la minore I L, la maggiore L M. </s>
<s>il contatto del<lb/>l'vna congiogatione all'altra il ponto L: è manifeſto che la veloci­<lb/>tà del ponto M, alla velocità del ponto K, è compoſta della ragion del<lb/>li diametri M I, ad I L, &amp; H L ad H K: che è l'iſteſſa, che di G ad E: <lb/>ma G ad E, è di maggior interuallo che di D a C. </s>
<s id="N114A5">
<expan abbr="Dũque">Dunque</expan>, poſta la poſſan<lb/>za tarda in K, la coſa moſſa con la circonferenza M, ſi mouerà <expan abbr="cõ">con</expan> mag<lb/>gior velocità della data. </s>
<s id="N114B2">Il che ſi hauea da trouare. <emph.end type="italics"/></s></p>
<pb xlink:href="041/01/069.jpg" pagenum="68"/>
<p id="N114B9" type="head">
<s id="N114BB"><emph type="italics"/>MOMENTI ACQVISTATI. <emph.end type="italics"/></s></p><p id="N114C1" type="main">
<s id="N114C3">Poniamo degli momenti, altri eſſer intrinſechi: al <lb/>tri acquiſtati, &amp; altri miſti: &amp; intrinſechi quelli, che <lb/>non da mouimento precedente dipendono: come ſono <lb/>gli mouimenti delle grauezze in giù, e del corpo leggiero <lb/>dentro l'humor più graue in sù. </s>
<s id="N114CD">Acquiſtati quelli, che ſe­<lb/>guono l'impreſsion fatta da precedente mouimento: come <lb/>il mouimento della coſa lanciata, che ſegue il <expan abbr="mouimẽto">mouimento</expan><lb/> del braccio, o della corda. </s>
<s id="N114D8">Miſti, come il mouimento delle <lb/>grauezze dopo l'hauer dato principio a mouerſi: per il che <lb/>veggiamo li peſi di vicino laſciati, mouerſi con minor mo­<lb/>mento, che laſciati di lontano: e molte coſe portate dalla <lb/>propria grauezza nell'aria penetrar ſotto l'accqua, con­<lb/>tro di quel che porta l'intrinſeco momento: onde dopo <lb/>l'eſſere affondate da ſe ſteſsi ritornar á galla. </s>
<s id="N114E6">Et il momen­<lb/>to intrinſeco eſſer l'iſteſſo ſempre. </s>
<s id="N114EA">l'acquiſtato, mancando <lb/>la cauſa di ponerſi, e con il tempo, e dall'impedimento che <lb/>le faccia reſiſtenza. <emph type="italics"/>CVGNO. <emph.end type="italics"/></s></p><p id="N114F5" type="main">
<s id="N114F7">Il cugno percoſſo, conſiderato in vn modo, rappreſenta <lb/>un piano inchinato, che ſi ſpinga ſotto il peſo. </s>
<s id="N114FB">Et altrimen<lb/>te rappreſenta due leue, che nelle loro ſtremità, facciano <lb/>l'vna all'altra ſottoleua, &amp; habbiano il peſo tra la poſſanza, <lb/>e'l ſottoleua. </s>
<s id="N11503">Et altrimente rappreſenta leua nel cui ſtremo <lb/>ſia il peſo, &amp; il ſottoleua tramezzo. <emph type="italics"/>VITE E CHIOCCIA. <emph.end type="italics"/></s></p><p id="N1150C" type="main">
<s id="N1150E">La vite, o chioccia rappreſenta vno o più piani auuolti <lb/>ad vn fuſello. </s>
<s id="N11512">Sono e maſchia, e femina: de quali vna ſtan­<lb/>do ferma, l'altra che gira ſoſtiene il peſo. </s>
<s id="N11516">acquiſta dunque for<lb/>za, <expan abbr="ſecõdo">ſecondo</expan> la detta inchinazione, e ſecondo la lunghezza del <lb/>raggio che ſe le accompagna. </s>
<s id="N11520">Vite perpetua diciamo vn <lb/>sympano con denti a vite, che girando tocchi rota dentata. </s><lb/>
<s id="N11525">Per il che accreſce la forza, e per la proprieta della vite, <lb/>e della congiogatione delle rote. </s></p><p id="N11529" type="head">
<s id="N1152B"><emph type="italics"/>IL FINE. <emph.end type="italics"/></s></p>
</chap>
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</archimedes>

